Question

我想从我的数据库中只导出一个表，然后通过PHP将其导入另一个数据库，我尝试在phpMyAdmin中执行此操作，我从.sql（和gzipped）中的sql-1导出然后导入到sql-2，但是当导出完成后，它只会显示一个空白页面。所以我想通过PHP来做到这一点。我有整个数据库的导出/导入代码，但我只想导入/导出一个特定的表。

这是我的代码：

导入

<?php
//ENTER THE RELEVANT INFO BELOW
$mysqlDatabaseName ='db123456789';
$mysqlUserName ='dbo123456789';
$mysqlPassword ='yourPassword';
$mysqlHostName ='db1234.perfora.net';
$mysqlImportFilename ='yourMysqlBackupFile.sql';

//DO NOT EDIT BELOW THIS LINE
//Export the database and output the status to the page
$command='mysql -h' .$mysqlHostName .' -u' .$mysqlUserName .' -p' .$mysqlPassword .' ' .$mysqlDatabaseName .' < ' .$mysqlImportFilename;
exec($command,$output=array(),$worked);
switch($worked){
case 0:
echo 'Import file <b>' .$mysqlImportFilename .'</b> successfully imported to database <b>' .$mysqlDatabaseName .'</b>';
break;
case 1:
echo 'There was an error during import. Please make sure the import file is saved in the same folder as this script and check your values:<br/><br/><table><tr><td>MySQL Database Name:</td><td><b>' .$mysqlDatabaseName .'</b></td></tr><tr><td>MySQL User Name:</td><td><b>' .$mysqlUserName .'</b></td></tr><tr><td>MySQL Password:</td><td><b>NOTSHOWN</b></td></tr><tr><td>MySQL Host Name:</td><td><b>' .$mysqlHostName .'</b></td></tr><tr><td>MySQL Import Filename:</td><td><b>' .$mysqlImportFilename .'</b></td></tr></table>';
break;
}
?>

导出：

<?php
//ENTER THE RELEVANT INFO BELOW
$mysqlDatabaseName ='db123456789';
$mysqlUserName ='dbo123456789';
$mysqlPassword ='myPassword';
$mysqlHostName ='db1234.perfora.net';
$mysqlExportPath ='chooseFilenameForBackup.sql';

//DO NOT EDIT BELOW THIS LINE
//Export the database and output the status to the page
$command='mysqldump --opt -h' .$mysqlHostName .' -u' .$mysqlUserName .' -p' .$mysqlPassword .' ' .$mysqlDatabaseName .' > ~/' .$mysqlExportPath;
exec($command,$output=array(),$worked);
switch($worked){
case 0:
echo 'Database <b>' .$mysqlDatabaseName .'</b> successfully exported to <b>~/' .$mysqlExportPath .'</b>';
break;
case 1:
echo 'There was a warning during the export of <b>' .$mysqlDatabaseName .'</b> to <b>~/' .$mysqlExportPath .'</b>';
break;
case 2:
echo 'There was an error during export. Please check your values:<br/><br/><table><tr><td>MySQL Database Name:</td><td><b>' .$mysqlDatabaseName .'</b></td></tr><tr><td>MySQL User Name:</td><td><b>' .$mysqlUserName .'</b></td></tr><tr><td>MySQL Password:</td><td><b>NOTSHOWN</b></td></tr><tr><td>MySQL Host Name:</td><td><b>' .$mysqlHostName .'</b></td></tr></table>';
break;
}
?>

Answer 1

你为什么不只使用MySQL？

CREATE TABLE your_NEW_db_name.your_new_table_name LIKE your_db_name.your_old_table_name;

INSERT your_NEW_db_name.your_new_table_name SELECT * FROM your_db_name.your_old_table_name;

仅将一个表从数据库导入/导出到另一个[通过PHP]

1 个答案: