无法将值NULL插入列中

时间:2014-05-10 19:08:08

标签: c# mysql sql sql-server

HY,

我为数据库创建了以下3个表:

CREATE TABLE [dbo].[Buyer] (
[Buyer_Id]   INT           IDENTITY (1, 1) NOT NULL,
[Last_Name]  NVARCHAR (50) NOT NULL,
[First_Name] NVARCHAR (50) NOT NULL,
[Social_No]  NVARCHAR (50) NOT NULL,
[Phone]      NVARCHAR (50) NOT NULL,
[User_Id]    INT           NOT NULL,
PRIMARY KEY CLUSTERED ([Buyer_Id] ASC),
CONSTRAINT [FK_User_Id] FOREIGN KEY ([User_Id]) REFERENCES [dbo].[User] ([User_Id])

);

CREATE TABLE [dbo].[Type] (
    [Type_Id]   INT        IDENTITY (1, 1) NOT NULL,
    [Type_Name] NCHAR (10) NULL,
    PRIMARY KEY CLUSTERED ([Type_Id] ASC)
);

CREATE TABLE [dbo].[User] (
    [User_Id] INT           IDENTITY (1, 1) NOT NULL,
    [User_Name]    NCHAR (10)    NOT NULL,
    [Pass]    NVARCHAR (50) NOT NULL,
    [Type_Id] INT           NOT NULL,
    PRIMARY KEY CLUSTERED ([User_Id] ASC),
    CONSTRAINT [FK__Type_Id] FOREIGN KEY ([Type_Id]) REFERENCES [dbo].[Type] ([Type_Id])
);

我有以下存储过程

    CREATE PROCEDURE [dbo].[InsertCustomer]
    @Buyer_Id int output,
    @Last_Name varchar(50),
    @First_Name varchar(50),
    @Social_No varchar(50),
    @Phone varchar(50),
    @User_Id int output,
    @User_Name nchar(10),
    @Pass varchar(50),
    @Type_id int output,
    @Type_Name nchar(10)

    AS
     BEGIN

    SET NOCOUNT ON;  

    insert into Buyer(Last_Name,First_Name,Social_No,Phone)
    values (@Last_Name,@First_Name,@Social_No,@Phone)
    set @Buyer_Id = SCOPE_IDENTITY();  

    insert into [User](User_Name,Pass)
    values(@User_Name,@Pass)
    set @User_Id = SCOPE_IDENTITY();  


    insert into [Type](Type_Name)
    values (@Type_Name)
    set @Type_id = SCOPE_IDENTITY();    

    RETURN 0

 END

和C#代码:

SqlCommand cmd = new SqlCommand("InsertCustomer", conn);
            cmd.CommandType = CommandType.StoredProcedure;
            SqlParameter paramLastName = new SqlParameter("@Last_Name", customer.Last_Name);
            SqlParameter paramFirstName = new SqlParameter("@First_Name", customer.First_Name);
            SqlParameter paramSocialNo = new SqlParameter("@Social_No", customer.Social_No);
            SqlParameter paramPhone = new SqlParameter("@Phone", customer.Phone_No);
            SqlParameter paramUserName = new SqlParameter("User_name", user.User_Name);
            SqlParameter paramPass = new SqlParameter("@Pass", user.Pass);
            SqlParameter paramTypeName = new SqlParameter("@Type_Name", type.Type_Name);
            SqlParameter paramBuyerId = new SqlParameter("@Buyer_Id", SqlDbType.Int);
            paramBuyerId.Direction = ParameterDirection.Output;
            SqlParameter paramUserId = new SqlParameter("@User_Id", SqlDbType.Int);
            paramUserId.Direction = ParameterDirection.Output;
            SqlParameter paramTypeId = new SqlParameter("@Type_Id", SqlDbType.Int);
            paramTypeId.Direction = ParameterDirection.Output;
            cmd.Parameters.Add(paramLastName);
            cmd.Parameters.Add(paramFirstName);
            cmd.Parameters.Add(paramSocialNo);
            cmd.Parameters.Add(paramPhone);
            cmd.Parameters.Add(paramUserName);
            cmd.Parameters.Add(paramPass);
            cmd.Parameters.Add(paramTypeName);
            cmd.Parameters.Add(paramBuyerId);
            cmd.Parameters.Add(paramUserId);
            cmd.Parameters.Add(paramTypeId);

            conn.Open();
            cmd.ExecuteNonQuery();
            customer.Buyer_Id = (int)paramBuyerId.Value;
            type.Type_Id = (int)paramTypeId.Value;
            user.User_Id = (int)paramUserId.Value;

但是在我将数据插入使用上述代码的表单后,我收到以下错误:

  

无法将值NULL插入列' User_Id' ....   PLATFORM.MDF.dbo.Buyer&#39 ;;列不允许空值。 INSERT失败。

     

无法将值NULL插入列' Type_Id',表格...   PLATFORM.MDF.dbo.User&#39 ;;列不允许空值。 INSERT失败。

请帮助我,

此致

2 个答案:

答案 0 :(得分:1)

存储过程中存在错误,因为您没有为User_Id或Type_Id列指定值,但这些列不允许使用空值。

您应该颠倒插入的顺序,并在以下部分中使用生成的标识值,如下所示:

insert into [Type](Type_Name)
values (@Type_Name)
set @Type_id = SCOPE_IDENTITY();    

insert into [User](User_Name,Pass,TypeId)
values(@User_Name,@Pass,@Type_id)
set @User_Id = SCOPE_IDENTITY();  

insert into Buyer(Last_Name,First_Name,Social_No,Phone,User_Id)
values (@Last_Name,@First_Name,@Social_No,@Phone,@User_Id)
set @Buyer_Id = SCOPE_IDENTITY();  

答案 1 :(得分:1)

您应该更改插入顺序。首先,您应该插入新类型

insert into [Type](Type_Name)
values (@Type_Name)
set @Type_id = SCOPE_IDENTITY();  

之后你应该插入新用户(使用@type_id)

insert into [User](User_Name,Pass,Type_id)
values(@User_Name,@Pass,@Type_id)
set @User_Id = SCOPE_IDENTITY();  

Filnaly,使用@User_Id插入买方。反过来使用@User_Id

insert into Buyer(Last_Name,First_Name,Social_No,Phone,User_id)
values (@Last_Name,@First_Name,@Social_No,@Phone,@User_Id)
set @Buyer_Id = SCOPE_IDENTITY();