Question

我见过很多JAXB实现，我们可以使用@XmlElement注释将java原语转换为XML元素。

但是，我想将以下POJO转换为XML（注意员工类中有一个地址 object 而不仅仅是原语）：

public class Employee {
    private Address address;
    private int employeeId;

    // constructors + setters + getters
}

如何使用这些JAXB注释将员工对象编组为XML？

感谢。

Answer 1

你需要做的就是编组一个POJO属性与编组一个原始属性。引用的POJO类不需要使用@XmlRootElement进行注释。

Java模型

<强>员工

import javax.xml.bind.annotation.XmlRootElement;

@XmlRootElement
public class Employee {

    private Address address;
    private int employeeId;

    public Address getAddress() {
        return address;
    }

    public void setAddress(Address address) {
        this.address = address;
    }

    public int getEmployeeId() {
        return employeeId;
    }

    public void setEmployeeId(int employeeId) {
        this.employeeId = employeeId;
    }

}

<强>地址

将Address作为Employee的一部分进行编组，您无需做任何特殊工作。

public class Address {

    private String street;

    public String getStreet() {
        return street;
    }

    public void setStreet(String street) {
        this.street = street;
    }

}

演示代码

下面是一些演示代码，它将填充和员工模型并将其编组为XML。

<强>演示

import javax.xml.bind.*;

public class Demo {

    public static void main(String[] args) throws Exception {
        JAXBContext jc = JAXBContext.newInstance(Employee.class);

        Address address = new Address();
        address.setStreet("1 A Street");

        Employee employee = new Employee();
        employee.setEmployeeId(123);
        employee.setAddress(address);

        Marshaller marshaller = jc.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
        marshaller.marshal(employee, System.out);
    }

}

<强>输出

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<employee>
    <address>
        <street>1 A Street</street>
    </address>
    <employeeId>123</employeeId>
</employee>

重命名Marshalled Element

如果要覆盖默认元素名称，则可以使用@XmlElement注释，无论属性的类型如何。

<强>员工

import javax.xml.bind.annotation.*;

@XmlRootElement
public class Employee {

    private Address address;
    private int employeeId;

    @XmlElement(name="ADDR")
    public Address getAddress() {
        return address;
    }

    public void setAddress(Address address) {
        this.address = address;
    }

    @XmlElement(name="ID")
    public int getEmployeeId() {
        return employeeId;
    }

    public void setEmployeeId(int employeeId) {
        this.employeeId = employeeId;
    }

}

<强>输出

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<employee>
    <ADDR>
        <street>1 A Street</street>
    </ADDR>
    <ID>123</ID>
</employee>

Answer 2

使用Jaxb，您可以尝试以下代码。或者，您可以尝试Xstream

  @XmlRootElement
public class TestObject {

    String a;

    TestObject1 anotherObject;
    public String getA() {
        return a;
    }
    @XmlElement
    public void setA(String a) {
        this.a = a;
    }


    public TestObject1 getAnotherObject() {
        return anotherObject;
    }
    @XmlElement
    public void setAnotherObject(TestObject1 anotherObject) {
        this.anotherObject = anotherObject;
    }
    public static void main(String[] args) throws JAXBException {
        TestObject object = new TestObject();
        object.setA("A");
        TestObject1 anotherObject = new TestObject1();
        anotherObject.setB("B");
        object.setAnotherObject(anotherObject);
        File file = new File("output.xml");
        JAXBContext jaxbContext = JAXBContext.newInstance(TestObject.class);
        Marshaller jaxbMarshaller = jaxbContext.createMarshaller();
        jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);

        jaxbMarshaller.marshal(object, file);
        jaxbMarshaller.marshal(object, System.out);
    }
}

========================

@XmlRootElement
public class TestObject1 {

    String b;

    public String getB() {
        return b;
    }

    @XmlElement
    public void setB(String b) {
        this.b = b;
    }

}

Answer 3

我能够在对象内实现对象＆＃34;通过下面给出的appraoch（即通过使用@XmlRootElement注释注释两个类）对JAXB进行XML编组：

import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;

@XmlRootElement
public class Employee {
    @XmlElement
    private Address address;
     .
     .
}

@XmlRootElement
public class Address {
    .
    .
}

如何使用@XmlElement和@XmlRootElement来编组对象内的对象？

3 个答案:

Java模型

演示代码

重命名Marshalled Element