Question

我有一个查询，用于选择树状结构中每个部门的金额。我想在各自的父母身上显示孩子的总金额。

是否可以在不使用游标的情况下将其存档在查询中？

以下是要总结的数据的结果集。也可以在sqlfiddle上找到完整的样本。

| DEPARTMENT_ID | PARENT_DEP_ID |     DEPARTMENT |          AMOUNT |
|---------------|---------------|----------------|-----------------|
|             1 |             0 |              1 |               0 |
|             7 |             1 |             11 |               0 |
|            34 |             7 |            111 |               0 |
|           120 |            34 |           1111 |               0 |
|           402 |           120 |         111101 |               0 |
|           651 |           402 | 11110101/10000 | 227470.72339635 |
|           651 |           402 | 11110101/10000 |  52255.99610869 |
|           651 |           402 | 11110101/10000 |   4437.15281795 |
|           651 |           402 | 11110101/10000 |   4552.70289465 |
|           651 |           402 | 11110101/10000 |   8510.61790448 |
|           651 |           402 | 11110101/10000 |         8266.08 |
|           651 |           402 | 11110101/10000 |         9968.16 |
|           651 |           402 | 11110101/10000 |          242.58 |
|           403 |           120 |         111102 |               0 | <= this is where i
|           652 |           403 | 11110201/10005 |  120384.7842412 |    want to have my
|           652 |           403 | 11110201/10005 | 488733.59476206 |    sum from the 
|           652 |           403 | 11110201/10005 |    2318.6573888 |    child items
|           652 |           403 | 11110201/10005 |  23690.22829273 |
|           652 |           403 | 11110201/10005 | 38321.261680815 |
|           652 |           403 | 11110201/10005 |         6199.56 |
|           652 |           403 | 11110201/10005 |         7476.12 |
|           652 |           403 | 11110201/10005 |          161.92 |

Answer 1

这将获得完整的报告

SELECT t1.DEPARTMENT_ID
     , t1.PARENT_DEP_ID
     , t1.DEPARTMENT   
     , Sum(t2.Amount) Amount
FROM   TREE_DATA t1
       INNER JOIN TREE_DATA t2 
       ON t1.DEPARTMENT = SUBSTR(t2.DEPARTMENT, 1, LENGTH(t1.DEPARTMENT))
WHERE  t1.Amount = 0
GROUP BY t1.DEPARTMENT_ID, t1.PARENT_DEP_ID, t1.DEPARTMENT

UNION ALL

SELECT DEPARTMENT_ID
     , PARENT_DEP_ID
     , DEPARTMENT   
     , Amount
FROM   TREE_DATA
WHERE  Amount > 0
ORDER BY DEPARTMENT

第一个查询通过黑客攻击没有金额的oens的部门名称结构获得滚动总和，第二个查询得到了叶子。
第一个查询无法显示叶子，因为它们将被分组。我没有找到任何列组合来获得相同的顺序，叶子似乎是无序的。

SQLFiddle演示

我尝试编写一个递归CTE，但是不可能有聚合函数，例如SUM。

Answer 2

with rec(parent_dep_id, department_id, depth) as ( 
  select cast(null as int), 403, 0 from dual 
  union all 
  select rec.department_id, t.department_id, depth+1 
  from rec
     , tree_data t
  where depth<100
    and rec.department_id = t.parent_dep_id
) select sum(t.amount)
  from rec
  join tree_data t
      on rec.department_id = t.department_id

可以通过在rec中包含金额来避免tree_data上的最终连接。

如何在SQL中从子项到父项的树状结构中总结数据？

2 个答案: