我正在尝试将下面的逗号分隔标签列表拆分为单个元素。 XML源中的元素和属性名称将始终相同。我使用1.0,所以我希望有1.0解决方案。基于this similar example我认为以下XSL可以工作:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output indent="yes"/>
<xsl:template match="pbcoreCollection">
<pbcoreCollection xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<pbcoreDescriptionDocument>
<xsl:call-template name="tokenize">
<xsl:with-param name="text" select="instantiationannotation"/>
<xsl:with-param name="elemName" select="'instantitionAnnotation'"/>
</xsl:call-template>
</pbcoreDescriptionDocument>
</pbcoreCollection>
</xsl:template>
<xsl:template name="tokenize">
<xsl:param name="text"/>
<xsl:param name="elemName"/>
<xsl:param name="sep" select="', '"/>
<xsl:choose>
<xsl:when test="contains($text, $sep)">
<xsl:element name="{$elemName}">
<xsl:value-of select="substring-before($text, $sep)"/>
</xsl:element>
<!-- recursive call -->
<xsl:call-template name="tokenize">
<xsl:with-param name="text" select="substring-after($text, $sep)" />
<xsl:with-param name="elemName" select="$elemName" />
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:element name="{$elemName}">
<xsl:value-of select="$text"/>
</xsl:element>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
</xsl:stylesheet>
但它会产生结果
<?xml version="1.0"?>
<pbcoreCollection xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<pbcoreDescriptionDocument>
<instantitionAnnotation/>
</pbcoreDescriptionDocument>
</pbcoreCollection>
我原来的XML:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<pbcoreCollection xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<pbcoreDescriptionDocument>
<pbcoreInstantiation>
<instantiationAnnotation annotationType="CMS tag">congress, guns, gun_policy, catholic_schools, social_media, </instantiationAnnotation>
</pbcoreInstantiation>
</pbcoreDescriptionDocument>
</pbcoreCollection>
我希望看起来像这样:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<pbcoreCollection xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<pbcoreDescriptionDocument>
<pbcoreInstantiation>
<instantiationAnnotation annotationType="CMS tag">congress</instantiationAnnotation>
<instantiationAnnotation annotationType="CMS tag">gun</instantiationAnnotation>
<instantiationAnnotation annotationType="CMS tag">gun_policy</instantiationAnnotation>
<instantiationAnnotation annotationType="CMS tag">catholic_schools</instantiationAnnotation>
<instantiationAnnotation annotationType="CMS tag">social_media</instantiationAnnotation>
</pbcoreInstantiation>
</pbcoreDescriptionDocument>
</pbcoreCollection>
答案 0 :(得分:0)
在这种情况下,是的,XML源中的元素和属性名称 永远都是一样的。
在这种情况下,您可以简化为:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/">
<pbcoreCollection xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<pbcoreDescriptionDocument>
<pbcoreInstantiation>
<xsl:call-template name="tokenize">
<xsl:with-param name="text" select="pbcoreCollection/pbcoreDescriptionDocument/pbcoreInstantiation/instantiationAnnotation"/>
</xsl:call-template>
</pbcoreInstantiation>
</pbcoreDescriptionDocument>
</pbcoreCollection>
</xsl:template>
<xsl:template name="tokenize">
<xsl:param name="text"/>
<xsl:param name="sep" select="', '"/>
<xsl:choose>
<xsl:when test="contains($text, $sep)">
<instantiationAnnotation annotationType="CMS tag">
<xsl:value-of select="substring-before($text, $sep)"/>
</instantiationAnnotation>
<!-- recursive call -->
<xsl:call-template name="tokenize">
<xsl:with-param name="text" select="substring-after($text, $sep)" />
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<instantiationAnnotation annotationType="CMS tag">
<xsl:value-of select="$text"/>
</instantiationAnnotation>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
</xsl:stylesheet>
注意:如果您的输入确实带有一个尾随的“,”分隔符,则可能需要更多工作,如示例所示。