在单个SELECT查询中获取两个表记录

Question

我试图在SELECT查询中交叉匹配2个表。此外，我还会过滤结果，以便在60天内仅回显记录。我使用PDO来做到这一点。

此代码有效：

   //$my_con->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
    foreach ($my_con->query("SELECT subject, date, name FROM table1") as $result){
         $gtTIme = $result['date'];
        $time = strtotime($gtTIme);
        $ftime = date("Y-m-d g:ia", $time);
        $days_ago = date('Y-m-d g:ia', strtotime('-60 days'));
        if ($ftime > $days_ago) { 
           $unl=$result['name'] . '<br />';
             echo("</option><option value=". $uml . ">". $result['name'] ."</option>");
        }
            };

此代码不起作用：

foreach ($my_con->query("SELECT subject, date, table1.name, score, studentname FROM table1 JOIN table2 ON table1.name = table2.studentname ORDER BY table2.score DESC") as $result){
                $gtname = $result['name'];
                $gtsubject = $result['subject'];
                $gtScore = $result['score'];
                $gtTIme = $result['date'];

    $time = strtotime($gtTIme);
    $ftime = date("Y-m-d g:ia", $time);
    $days_ago = date('Y-m-d g:ia', strtotime('-60 days'));
    if ($ftime > $days_ago) { 
       $unl=$result['name'] . '<br />';
         echo("</option><option value=". $uml . ">". $result['name']."</option>");
    }
        };

表1

name  |  subject  |  date
------+-----------+----------
Kyle  |  Science  | 2014-04-03 4:00pm
John  |  Science  | 2014-05-04 9:30am
Peter |  Maths    | 2013-10-20 9:30am

表2

score  |  studentname
-------+-------------
78     | John
89     | Kyle
83     | Peter

我希望回声是这样的：

Kyle   Science  89
JOHN   Science  78