numpy.delete将浮点数组更改为字符串

时间:2014-05-17 02:46:26

标签: python arrays string numpy

我使用numpy.delete函数从多个数组中删除元素。我从这个问题Make this simple for/if block more pythonic开始,在应用那里给出的答案之后到达:

# Data lists.
a = [3,4,5,12,6,8,78,5,6]
b = [6,4,1.,2,8,784.,43,6.,2]
c = [8,4.,32.,6,1,7,2.,9,23]

# Maximum limit.
max_limit = 20.

# Store indexes of elements to be removed.
indexes = [i for i, t in enumerate(zip(b, c)) if any(e > max_limit for e in t)]

# Remove elements from all lists.
big_array = np.array([a, b, c])
clean_array = np.delete(big_array, indexes, axis=1)

# Final clean lists.
a_clean, b_clean, c_clean = clean_array

我遇到的问题是我的一个列表实际上是由字符串而不是浮点数组成的,如下所示:

# Data lists.
a = ['a','b','c','d','e','f','g','h','i'] # <-- strings
b = [6,4,1.,2,8,784.,43,6.,2] # <-- floats
c = [8,4.,32.,6,1,7,2.,9,23] # <-- floats

当我应用上面的代码时,numpy.delete行会将所有最终列表a_clean, b_clean, c_clean)中的所有元素转换为字符串,而不是仅保留第一个作为字符串的字符串其余的作为花车。

如果无法帮助,我该如何防止这种情况发生或修复?

1 个答案:

答案 0 :(得分:1)

如果您打算使用numpy,那么将列表转换为数组会更好。它看起来像是:

a = np.array(a)
b = np.array(b)
c = np.array(c)

mask = (b > max_limit) | (c > max_limit)

a = a[mask]
b = b[mask]
c = c[mask]

>>> a
array(['c', 'f', 'g', 'i'],
      dtype='|S1')
>>> b
array([   1.,  784.,   43.,    2.])
>>> c
array([ 32.,   7.,   2.,  23.])