Question

我有以下数组：

[1] => Array
        (
            [entity_id] => 5877
            [parent_id] => 5862
            [label] => Railbikes
            [name] => railbikes
            [icon] => books.svg
            [level] => 5
            [tab_id] => 353
        )

    [2] => Array
        (
            [entity_id] => 5756
            [parent_id] => 5754
            [label] => Tournaments
            [name] => tournaments
            [icon] => books.svg
            [level] => 5
            [tab_id] => 354
        )

    [3] => Array
        (
            [entity_id] => 5756
            [parent_id] => 5754
            [label] => Tournaments
            [name] => tournaments
            [icon] => books.svg
            [level] => 5
            [tab_id] => 357
        )

在此数组标签中=＆gt;锦标赛重复两次，这是整个阵列的情况，许多标签重复两次，三次和很多次。我希望这个数组显示为会有一个唯一的标签，每个数组中的tab_id都是不同的。这个tab_id被追加到唯一标签上。最终的数组看起来应该是这样的。

[1] => Array
            (
                [entity_id] => 5877
                [parent_id] => 5862
                [label] => Railbikes
                [name] => railbikes
                [icon] => books.svg
                [level] => 5
                [tab_id] => 353
            )

        [2] => Array
            (
                [entity_id] => 5756
                [parent_id] => 5754
                [label] => Tournaments
                [name] => tournaments
                [icon] => books.svg
                [level] => 5
                [tab_id] => 354 , 357
            )

感谢。

Answer 1

$arr = array(1 => array
    (
        entity_id => 5877,
        parent_id => 5862,
        label => Railbikes,
        name => railbikes,
        icon => books.svg,
        level => 5,
        tab_id => 353
    ),

2 => array
    (
        entity_id => 5756,
        parent_id => 5754,
        label => Tournaments,
        name => tournaments,
        icon => books.svg,
        level => 5,
        tab_id => 354
    ),

3 => array
    (
        entity_id => 5756,
        parent_id => 5754,
        label => Tournaments,
        name => tournaments,
        icon => books.svg,
        level => 5,
        tab_id => 357
    )
    );


    print("<pre>");
    foreach ($arr AS $key => $value){
        /*foreach ($value AS $innerKey => $innerValue){

        }*/

        if($arr[$key]['label']  == $arr[$key-1]['label'] )
        {
            $newArr[$key-1]['tab_id'] = $arr[$key]['tab_id'].",". $arr[$key-1]['tab_id'];
        }
        else{
            $newArr[$key]= $arr[$key];
        }
    }
            print_r($newArr);

Answer 2

如果entity_id总是相同，那么你可以“欺骗”一点：

$new_array = array();
foreach($array as $item)
{
    if(!isset($new_array[$item['entity_id']]) $new_array[$item['entity_id']] = $item;
}

$new_array = array_values($new_array);

PS：总是试图阻止双重数据，不会让你的脚本更快;）

Answer 3

试试这个

$new_array = array();
$items = array();

foreach( $array as $item )
{
    $check = array_search( $item['entity_id'], $items, true ); 
    if ( $check === false )
    {
        $temp = $item;
        $temp['tab_id'] = array( $item['tab_id'] );
        $new_array[] = $temp;
        $items[] = $temp['entity_id'];
    }
    else
    {
        $new_array[$check]['tab_id'][] = $item['tab_id'];
    }
}

其中$array是您向我们展示的原始数组。如果要在其余代码中保留相同的名称，可以在最后用$array = $new_array;替换它。

此外，请注意，tab_id现在是array以符合您的要求。

如果您真的想保留它，请使用

$new_array = array();
$items = array();

foreach( $array as $item )
{
    $check = array_search( $item['entity_id'], $items, true ); 
    if ( $check === false )
    {
        $new_array[] = $item;
        $items[] = $item['entity_id'];
    }
    else
    {
        $new_array[$check]['tab_id'] .= ', '.$item['tab_id'];
    }
}

Php数组迭代

3 个答案: