Question

我有以下XML：

<...>
  <...>
    <tabular>
        <time from="2014-05-22T10:00:00" to="2014-05-22T12:00:00" period="1">
          <symbol number="3" numberEx="3" var="03d" />
          <precipitation value="0" />
          <windDirection deg="191.8" code="SSW" />
          <windSpeed mps="1.3" />
          <temperature unit="celsius" value="16" />
          <pressure unit="hPa" value="1010.6" />
        </time>
        <time from="2014-05-22T10:00:00" to="2014-05-22T12:00:00" period="1">
          <symbol number="3" numberEx="3" var="03d" />
          <precipitation value="0" />
          <windDirection deg="191.8" code="SSW" />
          <windSpeed mps="1.3" />
          <temperature unit="celsius" value="16" />
          <pressure unit="hPa" value="1010.6" />
        </time>
        <time from="2014-05-22T10:00:00" to="2014-05-22T12:00:00" period="1">
          <symbol number="3" numberEx="3" var="03d" />
          <precipitation value="0" />
          <windDirection deg="191.8" code="SSW" />
          <windSpeed mps="1.3" />
          <temperature unit="celsius" value="16" />
          <pressure unit="hPa" value="1010.6" />
        </time>

我已经使用LINQ管理以获取表格列表：

var tabular = doc.Root.Descendants("tabular").ToList();

表格计数现在是1.我想要的是表格的子项列表。我已经尝试了额外的后代：

var tabular = doc.Root.Descendants("tabular").Descendants().ToList();

但是返回表格的每个后代的列表，导致列表中的时间，符号，降水等等。如何获得列表中包含表格的时间节点的列表？

我想要一个所有时间节点的列表，所以我可以将它序列化为一个对象并访问值

Answer 1

如果您只想获得Elements的直接子女

，请使用Descendants代替tabular

var tabular = doc.Root.Descendants("tabular").Elements().ToList();

更新：将时间元素解析为对象的提示

var times =
    from t in xdoc.Descendants("tabular").Elements()
    let symbol = t.Element("symbol")
    let temperature = t.Element("temperature")
    select new
    {
        From = (DateTime)t.Attribute("from"),
        To = (DateTime)t.Attribute("to"),
        Period = (int)t.Attribute("period"),
        Symbol = new
        {
            Number = (int)symbol.Attribute("number"),
            NumberEx = (int)symbol.Attribute("numberEx"),
            Var = (string)symbol.Attribute("var")
        },
        Precipitation = (int)t.Element("precipitation").Attribute("value"),
        WindSpeed = (double)t.Element("windSpeed").Attribute("mps"),
        Temperature = new
        {
            Unit = (string)temperature.Attribute("unit"),
            Value = (string)temperature.Attribute("value")
        }
    };

输出：

[
  {
    From: "2014-05-22T10:00:00",
    To: "2014-05-22T12:00:00",
    Period: 1,
    Symbol: { Number: 3, NumberEx: 3, Var: "03d" },
    Precipitation: 0,
    WindSpeed: 1.3,
    Temperature: { Unit: "celsius", Value: "16" }
  },
  // ...
]

如何选择节点的所有子节点，而不是所有后代？

1 个答案: