@ManyToMany额外专栏

时间:2014-05-25 02:50:17

标签: java hibernate jpa modeling

我需要模拟客户促销之间的关系。 我们需要有关客户促销得分 CLIENTS_PROMOTIONS_HISTORY 的历史记录以及当前得分 CLIENTS_PROMOTIONS

数据库建模很好,但我发现很难对实体进行建模。 我打算仅将 CLIENTS_PROMOTIONS 表用于关联目的,以便客户可以了解每次促销的促销+当前得分。但是无法找出存储当前分数的位置。

实体和图表:

@Entity
@Table(name = "CLIENTS")
@SecondaryTable(name = "CLIENTS_PROMOTIONS",
                pkJoinColumns = @PrimaryKeyJoinColumn(name = "ID_CLIENT"))
class Client {

    @Id
    @Column(name = "ID_CLIENT", nullable = false, unique = true)
    Long id;

    @OneToOne(cascade = CascadeType.ALL, optional = false)
    @JoinColumn(name = "ID_USER", nullable = false, unique = true)
    User user;

    @Column(name = "NAME", nullable = false)
    String name;

    @Column(name = "BIRTHDAY", nullable = false)
    Date birthday;

    @Column(name = "EMAIL", nullable = false)
    String email;

    @Column(name = "SEX", nullable = false)
    Character sex;

    @ManyToMany
    @JoinTable(name = "CLIENTS_PROMOTIONS", 
               joinColumns = @JoinColumn(name = "ID_CLIENT"),
               inverseJoinColumns = @JoinColumn(name = "ID_PROMOTION"))
    Set<Promotion> promotions;
}

-

@Entity
@Table(name = "PROMOTIONS")
class Promotion {

    @Id
    @Column(name = "ID_PROMOTION", nullable = false, unique = true)
    Long id;

    @Column(name = "ID_ESTABLISHMENT", nullable = false)
    Long establishmentId;

    @Column(name = "TITLE", nullable = false)
    String title;

    @Column(name = "LIMIT_SCORE", nullable = false)
    Long limitScore;

    @Column(name = "DESCRIPTION", nullable = false)
    String description;

    @Column(name = "REWARD", nullable = false)
    String reward;
}

my eer diagram

1 个答案:

答案 0 :(得分:0)

您需要为此<{1}}与促销和<建立 Client_Promotions 并建立Entity关系@ManyToOne strong>客户端实体,而不是Entity

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