无法将整数强制转换为java.util.HashMap

时间:2014-05-27 10:11:04

标签: android listview android-intent hashmap

我在android上使用listview,下面的代码在点击另一个新活动的列表项后给出了错误

@Override
            public void onItemClick(AdapterView<?> parent, View view,
                    int position, long id) {

                // getting list view size
                int size = parent.getCount();

                // initializing array according to list view size
                String[] all_pid = new String[size];
                String[] all_name = new String[size];
                String[] all_address = new String[size];
                String[] all_latitude = new String[size];
                String[] all_longitude = new String[size];

                // looping data into array according to getItemAtPosition
                for (int i = 0; i < size; i++) {
                    HashMap<String, String> extractor = (HashMap<String, String>) parent.getItemAtPosition(i);
                    // fill data into array
                    all_pid[i] = extractor.get("pid");
                    all_name[i] = extractor.get("name");
                    all_address[i] = extractor.get("address");
                    all_latitude[i] = extractor.get("latitude");
                    all_longitude[i]=extractor.get("longitude");
                }

                Intent in = new Intent(getApplicationContext(),SingleContactActivityMainFragment.class);

                in.putExtra("APid", all_pid);
                in.putExtra("AName", all_name);
                in.putExtra("AAddress", all_address);
                in.putExtra("ALatitude", all_latitude);
                in.putExtra("ALongitude", all_longitude);
                // added size for initial view pager initialization
                in.putExtra("size", size);
                in.putExtra("QUOTES", position);
                Log.v(DEBUG, "position Passed: " + position);
                startActivity(in);
            }

显示的错误是:

05-27 15:30:12.985: E/AndroidRuntime(23905): java.lang.ClassCastException: java.lang.Integer cannot be cast to java.util.HashMap
05-27 15:30:12.985: E/AndroidRuntime(23905):    at com.example.fightvaw.jsontest.MainActivity$4.onItemClick(MainActivity.java:226)

如何解决这些类型的错误?

3 个答案:

答案 0 :(得分:1)

这是我的自定义适配器上的先前代码:

@Override
public Object getItem(int position) {
    // TODO Auto-generated method stub
    return (position);
}

这解决了我的自定义适配器中的代码:

@Override
public Object getItem(int position) {
    // TODO Auto-generated method stub
    return data.get(position);
}

其中data被定义为ArrayList<HashMap<String, String>> data;

答案 1 :(得分:0)

这一行

HashMap<String, String> extractor = (HashMap<String, String>) parent.getItemAtPosition(i);

导致你的崩溃。 parent是一个AdapterView,如果您调用getItemAtPosition(i),则返回一个Integer。

您可以将parent替换为ListAdapter(您需要填充ListView)来解决此问题。之后您的代码应如下所示:

HashMap<String, String> extractor = youListAdapter.get(i);

答案 2 :(得分:0)

您的父AdapterView设计用于保存int值,它们会自动加到Integer。这就是为什么通过致电parent.getItemAtPosition(i)获得Integer。显然,Integer无法投放到HashMap

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