从字符串中提取值并将其存储在列表中

时间:2014-05-28 11:34:26

标签: python regex

我有一个字符串string

string = "get|Server ID:Server1,Server ID:Server2,Server ID:Server3,Query:SELECT * FROM sometable,_xsrf:57bsdkfnklbjhgfhjfghsndfsdfsdf"

get|,Query:之间的唯一内容是服务器ID

在我的示例中有3个服务器ID,但可以有更多

string = "get|Server ID:Server1,Server ID:Server2,Server ID:Server3,Server ID:Server4,Server ID:Server5,Query:SELECT * FROM sometable,_xsrf:57bsdkfnklbjhgfhjfghsndfsdfsdf"

我想选择所有服务器ID,例如server1,server2,server3等,并将它们放在列表中。

1 个答案:

答案 0 :(得分:4)

试试这个:

text = "get|Server ID:Server1,Server ID:Server2,Server ID:Server3...,Query:SELECT * FROM sometable,_xsrf:57bsdkfnklbjhgfhjfghsndfsdfsdf"

pattern = r'Server ID:([^,.]*),?'
result = re.findall(pattern, text)

print result

这是输出:

['Server1', 'Server2', 'Server3']
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