Question

function getBetween(content, start, end) {
    var r = content.split(start);
    if (1 in r) {
        var z = r[1].split(end);
        return z[0];
    }
    return '';
}

你好，我有以下函数，我写的可以在两个字符串之间得到一个字符串

例如

var string = 'I am 30 years old';
var age = getBetween(string, 'I am ', ' years old');

现在，如果字符串在年龄中出现的次数更多，例如string I am 30 years old I am 20 years old I am 50 years old

Etc等。我想知道是否有办法获得30,20,50和阵列中的其他任何匹配

Answer 1

您可以使用此功能：

function getBetween(content, start, end) {
   var arr = [];
   content.replace(new RegExp(start + "(.+)" + end,"g"),function(m,g1){ arr.push(g1); return '';});
   return arr;
}

var output = getBetween('I am 30 years old I am 20 years old I am 50 years old', 'I am ', ' years old');

输出：

["30", "20", "50"]

Answer 2

试试：

function getBetween(content, start, end) {
    var result = [];
    var r = content.split(start);
    for (var i = 1; i < r.length; i++) {
        result.push(r[i].split(end)[0]);
    }
    return result;
}

var output = getBetween('I am 30 years old I am 20 years old I am 50 years old', 'I am ', ' years old');

输出：

["30", "20", "50"]

Javascript在函数多个实例之间进行

2 个答案: