我正在尝试将Spring OAuth2用于我的其他应用。 但看起来我犯了一个错误，我可以找到我做的地方。 流程应该是： 1.使用用户名和密码从/ oauth / token获取令牌 2.使用提供的令牌向/ security发出请求
MethodSecurityConfig：
@Configuration
@EnableGlobalMethodSecurity(prePostEnabled = true, proxyTargetClass = true)
public class MethodSecurityConfig extends GlobalMethodSecurityConfiguration {
@Autowired
private SecurityConfiguration securityConfig;
@Override
protected MethodSecurityExpressionHandler createExpressionHandler() {
return new OAuth2MethodSecurityExpressionHandler();
}
}
OAuth2ServerConfig：
@Configuration
public class OAuth2ServerConfig {
private static final String RESOURCE_ID = "nessnity";
@Configuration
@Order(10)
protected static class UiResourceConfiguration extends WebSecurityConfigurerAdapter {
@Override
protected void configure(HttpSecurity http) throws Exception {
http
.requestMatchers().antMatchers("/security")
.and()
.authorizeRequests()
.antMatchers("/security").access("hasRole('USER')");
}
}
@Configuration
@EnableResourceServer
protected static class ResourceServerConfiguration extends ResourceServerConfigurerAdapter {
@Override
public void configure(ResourceServerSecurityConfigurer resources) {
resources.resourceId(RESOURCE_ID);
}
@Override
public void configure(HttpSecurity http) throws Exception {
http
.requestMatchers().antMatchers("/security/")
.and()
.authorizeRequests()
.antMatchers("/security").access("#oauth2.hasScope('read')");
}
}
@Configuration
@EnableAuthorizationServer
protected static class AuthorizationServerConfiguration extends AuthorizationServerConfigurerAdapter {
@Autowired
private TokenStore tokenStore;
@Autowired
private UserApprovalHandler userApprovalHandler;
@Autowired
private AuthenticationManager authenticationManager;
@Override
public void configure(ClientDetailsServiceConfigurer clients) throws Exception {
clients.inMemory()
.withClient("my-client")
.resourceIds(RESOURCE_ID)
.authorizedGrantTypes("client_credentials")
.authorities("ROLE_CLIENT")
.scopes("read")
.secret("password")
.accessTokenValiditySeconds(60);
}
@Bean
public TokenStore tokenStore() {
return new InMemoryTokenStore();
}
@Override
public void configure(AuthorizationServerEndpointsConfigurer endpoints) throws Exception {
endpoints
.tokenStore(tokenStore)
.userApprovalHandler(userApprovalHandler)
.authenticationManager(authenticationManager);
}
@Override
public void configure(AuthorizationServerSecurityConfigurer oauthServer) throws Exception {
oauthServer.realm("sparklr2/client");
}
}
protected static class Stuff {
@Autowired
private ClientDetailsService clientDetailsService;
@Autowired
private TokenStore tokenStore;
@Bean
public ApprovalStore approvalStore() throws Exception {
TokenApprovalStore store = new TokenApprovalStore();
store.setTokenStore(tokenStore);
return store;
}
@Bean
@Lazy
@Scope(proxyMode=ScopedProxyMode.TARGET_CLASS)
public SparklrUserApprovalHandler userApprovalHandler() throws Exception {
SparklrUserApprovalHandler handler = new SparklrUserApprovalHandler();
handler.setApprovalStore(approvalStore());
handler.setRequestFactory(new DefaultOAuth2RequestFactory(clientDetailsService));
handler.setClientDetailsService(clientDetailsService);
handler.setUseApprovalStore(true);
return handler;
}
}
}
SecurityConfiguration：
@Configuration
@EnableWebSecurity
public class SecurityConfiguration extends WebSecurityConfigurerAdapter {
@Override
protected void configure(AuthenticationManagerBuilder auth) throws Exception {
auth.inMemoryAuthentication()
.withUser("root")
.password("password")
.roles("USER");
}
@Override
public void configure(WebSecurity web) throws Exception {
web.ignoring().antMatchers("/oauth/uncache_approvals", "/oauth/cache_approvals");
}
@Override
@Bean
public AuthenticationManager authenticationManagerBean() throws Exception {
return super.authenticationManagerBean();
}
@Override
protected void configure(HttpSecurity http) throws Exception {
http
.authorizeRequests()
.anyRequest().hasRole("USER");
}
}
问题：当我尝试获取令牌时
curl --user root:password --data "grant_type=client_credentials" http://localhost:8080/oauth/token
我收到了消息：
{“error”：“invalid_client”，“error_description”：“客户端不好 凭证“}
第二个问题是如何在url params中传递用户名/密码，例如/ oauth / token？username = root＆amp; password = password？
感谢。
更新
我决定从头开始使用xml配置。
以下配置完美无缺：
<?xml version="1.0" encoding="UTF-8" ?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:oauth="http://www.springframework.org/schema/security/oauth2"
xsi:schemaLocation="http://www.springframework.org/schema/security/oauth2 http://www.springframework.org/schema/security/spring-security-oauth2-1.0.xsd
http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.2.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.1.xsd">
<http pattern="/oauth/token" create-session="stateless"
authentication-manager-ref="authenticationManager"
xmlns="http://www.springframework.org/schema/security">
<intercept-url pattern="/oauth/token" access="IS_AUTHENTICATED_FULLY"/>
<anonymous enabled="false"/>
<http-basic entry-point-ref="clientAuthenticationEntryPoint"/>
<custom-filter ref="clientCredentialsTokenEndpointFilter" before="BASIC_AUTH_FILTER"/>
<access-denied-handler ref="oauthAccessDeniedHandler"/>
</http>
<bean id="clientCredentialsTokenEndpointFilter"
class="org.springframework.security.oauth2.provider.client.ClientCredentialsTokenEndpointFilter">
<property name="authenticationManager" ref="authenticationManager"/>
</bean>
<authentication-manager alias="authenticationManager"
xmlns="http://www.springframework.org/schema/security">
<authentication-provider user-service-ref="clientDetailsUserService"/>
</authentication-manager>
<bean id="clientDetailsUserService"
class="org.springframework.security.oauth2.provider.client.ClientDetailsUserDetailsService">
<constructor-arg ref="clientDetails"/>
</bean>
<bean id="clientDetails" class="com.nessnity.api.security.OAuthClienDetailsService">
<property name="id" value="testuser"/>
<property name="secretKey" value="secret" />
</bean>
<bean id="clientAuthenticationEntryPoint"
class="org.springframework.security.oauth2.provider.error.OAuth2AuthenticationEntryPoint">
<property name="realmName" value="springsec/client"/>
<property name="typeName" value="Basic"/>
</bean>
<bean id="oauthAccessDeniedHandler"
class="org.springframework.security.oauth2.provider.error.OAuth2AccessDeniedHandler"/>
<oauth:authorization-server
client-details-service-ref="clientDetails"
token-services-ref="tokenServices">
<oauth:authorization-code/>
<oauth:implicit/>
<oauth:refresh-token/>
<oauth:client-credentials/>
<oauth:password authentication-manager-ref="userAuthenticationManager"/>
</oauth:authorization-server>
<authentication-manager id="userAuthenticationManager"
xmlns="http://www.springframework.org/schema/security">
<authentication-provider ref="customUserAuthenticationProvider">
</authentication-provider>
</authentication-manager>
<bean id="customUserAuthenticationProvider"
class="com.nessnity.api.security.OAuthUserAuthenticationProvider">
</bean>
<bean id="tokenServices"
class="org.springframework.security.oauth2.provider.token.DefaultTokenServices">
<property name="tokenStore" ref="tokenStore"/>
<property name="supportRefreshToken" value="true"/>
<property name="accessTokenValiditySeconds" value="900000000"/>
<property name="clientDetailsService" ref="clientDetails"/>
</bean>
<bean id="tokenStore"
class="org.springframework.security.oauth2.provider.token.store.InMemoryTokenStore"/>
<bean id="oauthAuthenticationEntryPoint"
class="org.springframework.security.oauth2.provider.error.OAuth2AuthenticationEntryPoint">
</bean>
<http pattern="/resources/**" create-session="never"
entry-point-ref="oauthAuthenticationEntryPoint"
xmlns="http://www.springframework.org/schema/security">
<anonymous enabled="false"/>
<intercept-url pattern="/resources/**" method="GET"/>
<custom-filter ref="resourceServerFilter" before="PRE_AUTH_FILTER"/>
<access-denied-handler ref="oauthAccessDeniedHandler"/>
</http>
<oauth:resource-server id="resourceServerFilter"
resource-id="springsec" token-services-ref="tokenServices"/>
</beans>
答案 0 :(得分：6)
我面对类似的事情，它在完成以下更改后起作用
在 AuthorizationServerConfiguration 类中替换
@Override
public void configure(AuthorizationServerSecurityConfigurer oauthServer) throws Exception {
oauthServer.realm("sparklr2/client");
}
使用以下代码
@Override
public void configure(AuthorizationServerSecurityConfigurer oauthServer) throws Exception {
//oauthServer.realm("sparklr2/client");
oauthServer.allowFormAuthenticationForClients();
}
和请求应该
/的OAuth /令牌grant_type =密码＆安培;范围=读+写＆安培; CLIENT_ID = yourclientId＆安培; client_secret =秘密＆安培;用户名=用户名和安培;密码= PWD
答案 1 :(得分：0)
在您的访问令牌请求中，您正在使用客户端凭据授予类型。 OAuth规范说，在client_credentials授权类型的情况下，您需要提供base64编码的client_id:client_secret作为基本授权标头。
例如，如果您的client_id为google且client_secret为x23r-ss56-rfg8-6yt6，则您需要将这些字符串添加为google:x23r-ss56-rfg8-6yt6，使用Base64编码器对其进行编码并以
curl --header "Authorization: Basic <base64 encoded_string>" --data "grant_type=client_credentials" http://localhost:8080/oauth/token