Question

我需要一些帮助来为一个tic tac toe游戏设计一个简单的AI。我需要计算机在转弯时将2放在下一个可用的插槽上。这是初学者的日食编程课程，但教授休病假并停止回答问题！任何帮助将不胜感激！我在最后的ComputerInput [] []。

上遇到了问题

package lab15;

public class WinnerCheck {

    public static int PL_ONE = 1;
    public static int PL_TWO = 2;
    static Console console = new Console();
    static final int PAUSE      = 500;

    public static int[][] b = { { 0, 0, 0 }, { 0, 0, 0 }, { 0, 0, 0 } };


    public static void main(String[] args) {
        boolean done = false;

        while (!done) {
            printBoard(b);
            playerOneInput();
            pause(PAUSE);
            detectWinner(b);
            console.clear();
        }
    }

    public static void pause(int ms) {
        try {
            Thread.sleep(ms);
        } catch (Exception ex) {

        }
    }


    public static void placePiece(int[][] b, int r, int c, int player) {
        b[r][c] = player;
    }

    public static boolean isWinner(int[][] b, int player) {
        // check for a horizontal winner
        for (int i = 0; i < b.length; i++) {
            int count = 0;
            for (int j = 0; j < b[i].length; j++) {
                if (b[i][j] == player
                    || b[j][i] == player ) {
                    count++;
                }
            }
            if (count == b[i].length)
                return true;
        }
        return false;
    }

    public static int detectWinner(int[][] b) {
        if (isWinner(b, PL_ONE)) {
            return 1;
        } else if (isWinner(b, PL_TWO)) {
            return 2;
        } else {
            return 0;
        }
    }

    public static void printBoard(int[][] b) {
        System.out.println("------");
        for (int[] row : b) {
            for (int element : row) {
                System.out.print(element + " ");
            }
            System.out.println("");
        }
        System.out.println("------");
        System.out.println("winner: " + detectWinner(b));
    }


    public static void playerOneInput() {
        switch (console.getKey()) {
        case '1':
            placePiece (b, 0, 0, 1);
            break;
        case '2':
            placePiece (b, 0, 1, 1);
            break;
        case '3':
            placePiece (b, 0, 2, 1);
            break;
        case '4':
            placePiece (b, 1, 0, 1);
            break;
        case '5':
            placePiece (b, 1, 1, 1);
            break;
        case '6':
            placePiece (b, 1, 2, 1);
            break;
        case '7':
            placePiece (b, 2, 0, 1);
            break;
    case '8':
            placePiece (b, 2, 1, 1);
            break;
    case '9':
            placePiece (b, 2, 2, 1);
            break;
        }
    }

    public static int computerInput(int[][]b) {
        int a[] = {-1, -1};
        for (int i = 0; i < b.length; i++) {
            for (int j = 0; j < b[i].length; j++) {
                if (b(0)) {

                }
            }

        }
    }

}

Answer 1

你只需要检查b [i，j]是否等于0.如果是，则输入2并返回

如何做基本的AI

1 个答案: