Question

我正在努力使这个表格在这里显示基于网站类型的某些字段。在这种情况下，我希望它显示project.type == Website。

时的表单

然而我一直在

undefined method `type' for #<Project::ActiveRecord_Relation:0x007ffe1cb543a8>

我确信我可以正常调用.type，因为它可以在控制台中运行。

以下是我的文件：

#views/assets/_new_asset.html.erb
<%= simple_form_for @asset do |f| %>
<% if @project.type == 'Website' %>
  <%= f.input :name %>
  <%= f.input :url %>
  <%= f.button :submit %>
<% end %>
<% end %>

这是我的资产/控制器

#controller/assets_controller.rb
class AssetsController < ApplicationController

    def new
        @asset = Asset.new
        project = Asset.where(:project_id)
        @project = Project.where(:id == project)
        end


    def create
        @asset = current_user.assets.build(asset_params)

    if @asset.save
      flash[:notice] = "Asset successfully added."
      redirect_to(@project, :action => 'show')
    else
      render(:action => 'new')
    end
  end

  private

  def asset_params
    params.require(:asset).permit(:id, :type,:url, :page_rank, :rev_company ,:social_pages)
  end



end

Answer 1

好吧，你回来的是 ActiveRecord::Relation 的对象，而不是你的 model instance ，因此错误是因为没有方法叫< type 中的强> ActiveRecord::Relation 。

这应该有效

@project = Project.where(:id == project).first

或

你也可以这样做

<% if @project.first.type == 'Website' %>

执行 @project.first.type 是有效的，因为 @project.first 正在返回 {{1}找到的模型的第一个实例}

Answer 2

#views/assets/_new_asset.html.erb
<%= simple_form_for @asset do |f| %>
     <% if (@project.type == 'Website') %>
     <%= f.input :name %>
     <%= f.input :url %>
     <%= f.button :submit %>
     <% else %>
     You Should not see this line. 
<% end %>

在控制器

中

#controller/assets_controller.rb
class AssetsController < ApplicationController

    def new
        @asset = Asset.new
        # As if i have no idea from where youre getting :project_id
        # in your code so i changed that. add that to asset_params
        # if required. Thanks!!!
        @project = Project.where(id: params[:project_id]).take
    end

    def create
        @asset = current_user.assets.build(asset_params)

       if @asset.save
        flash[:notice] = "Asset successfully added."
        redirect_to(@project, :action => 'show')
      else
        render(:action => 'new')
      end
   end

  private

  def asset_params
    params.require(:asset).permit(:id, :type,:url, :page_rank, :rev_company ,:social_pages)
  end

end

查看无法识别模型属性？轨道

2 个答案: