Question

我有一张桌子

ReferenceNo |  Description | Amount
--------------------------------
    1222        abcd         30
    1223        efgh         10
    1223        ijkl         10
    1224        mnop         15
    1224        qrst          5
    1225        uvwx         33

我想要这样的输出：

 ReferenceNo |  Description | Amount
 --------------------------------
    1222        abcd         30
    1223        efgh ijkl    20                        
    1224        mnop qrst    20                     
    1225        uvwx         33

这里referenceNo重复我要添加金额，需要通过引用连接描述组

请帮我解决这个问题

Answer 1

我不确定是否有更简单的方法，但您可以使用FOR XML PATH输出使用子查询来实现

SELECT RefernceNo, 
     (SELECT Description + ' ' FROM [table] t2
      WHERE t2.ReferenceNo = t1.ReferenceNo FOR XML PATH('')
     ),
     SUM(Amount)
 FROM [table] as t1
 GROUP BY RefernceNo

Answer 2

虽然查询有点冗长但使用基本SQL。使用以下查询。使其成为3部分，1。获得计数，2。获得连接值，3。获得非重复描述，最后将所有这些描述加在一起。在此处查看演示http://sqlfiddle.com/#!3/10d2d/21。

SELECT REFERENCENO,NEWDESC,Total FROM
(
select X.REFERENCENO,X.NEWDESC,Y.Total,
ROW_NUMBER() OVER(PARTITION BY X.REFERENCENO 
 ORDER BY X.REFERENCENO DESC) as rn
from
(
select distinct t1.ReferenceNo,
t1.Description + t2.Description as NewDesc
from table1 t1
join table1 t2 
on t1.ReferenceNo = t2.ReferenceNo
and t1.Description <> t2.Description

union all

select [ReferenceNo], 
[Description]
from table1
where ReferenceNo in 
(
 select ReferenceNo from table1
group by [ReferenceNo]
having count(ReferenceNo) = 1
 )
) X 
inner join 
(
  select ReferenceNo,
sum(Amount) as Total
from table1
group by ReferenceNo
  ) Y
on X.ReferenceNo = Y.ReferenceNo
) TAB where rn = 1

Group with with sumatenate values with sum

2 个答案: