如何替换＆＃34; {#text [＆＃39; .. * var1 * ..＆＃39;] [.. * var2 * ..]}＆＃34; =＆GT; {$文本[＆＃39; * VAR1 * ..＆＃39;] [.. * * VAR2 ..]}

Question

我有这个文本数组

$text = array( "T02" => array( 'EN' => 'English text for T02'), 
           "T03" => array( 'FR' => 'Texte anglais pour T03'));
$language = "FR";
$testtext = "Translated text: {#text['T03'][$language]}";   

我需要＃here，因为我通过函数从数据库中获取此文本。

所以我需要用$

替换de＃

// This will work, but I need 'T03' and $language to be variable:

$output = str_replace("{#text['T03'][$language]}","{$text['T03'][$language]}",$testtext); 
echo $output;

// This won't work:
$output = str_replace("#text","$text",$testtext);
echo $output;   // I get ==> Translated text: {Array['T03'][FR]} 

如何替换＆＃34; {#text [＆＃39; .. var1 ..＆＃39;] [.. var2 ..] }＆＃34; ==＆GT; {$ text [＆＃39; .. var1 ..＆＃39;] [.. var2 ..]}？

Answer 1

使用preg_replace

<?php
$text = "{#text['..var1..'][..var2..]}";
$pattern = '/{#(.*)/';
echo preg_replace($pattern, '{\$$1', $text);

@Eduard，你不知道你在想什么。请用这个。它仍然很糟糕，但至少不会让你失望。

<?php
$text = array( "T02" => array( 'EN' => 'English text for T02'), 
           "T03" => array( 'FR' => 'Texte anglais pour T03'));
$language = "'FR'";
$testtext = "Translated text: {#text['T03'][$language]}"; 
$pattern = '/{#(?P<varName>\S+)\[\'(?P<someKey>\S+)\'\]\[\'(?P<langKey>\S+)\'\]}/';

$callback = function($match)use($text){
    return $text[$match['someKey']][$match['langKey']];
};
echo preg_replace_callback($pattern,$callback, $testtext);

如有特殊要求，所有理智都会在这里结束。输入风险自负！

<?php
$text = array( "T02" => array( 'EN' => 'English text for T02'), 
           "T03" => array( 'FR' => 'Texte anglais pour T03'));
$language = "'FR'";
$testtext = "Translated text: {#text['T03'][$language]}"; 
$pattern = '/{#(.*?)}/';


echo eval('return "'.preg_replace($pattern, '{\$$1}', $testtext).'";');