Question

我尝试将某个键下的值与[PFUser currentUser]值匹配。但是，当我记录下来时，我注意到它列出了所有PFUser属性。如果有某种方法可以查看某个值是否与[PFUser currentUser]匹配？

PFQuery *queryForMatchedLikes = [PFQuery orQueryWithSubqueries:@[firstToUserQuery, secondToUserQuery]];
[queryForMatchedLikes findObjectsInBackgroundWithBlock:^(NSArray *objects, NSError *error) {
    if (!error) {
        self.matches = [objects mutableCopy];   
        if ([self.matches count] == 0) {
            NSLog(@"No matches yet");
        } else {
            for (PFObject *match in self.matches) {
                if (match[kDDActivityFirstToUserKey] == [PFUser currentUser]) {
                    NSLog(@"first event");
                } else if (match[kDDActivitySecondToUserKey] == [PFUser currentUser]) {
                    NSLog(@"second event");
                }
            }
        } 
    }
}];

Answer 1

我通过找到两个值的objectId来解决这个问题。

PFQuery *queryForMatchedLikes = [PFQuery orQueryWithSubqueries:@[firstToUserQuery, secondToUserQuery]];
[queryForMatchedLikes findObjectsInBackgroundWithBlock:^(NSArray *objects, NSError *error) {
    if (!error) {
        self.matches = [objects mutableCopy];   
        if ([self.matches count] == 0) {
            NSLog(@"No matches yet");
        } else {
            for (PFObject *match in self.matches) {
                if ([[match[kDDActivityFirstToUserKey] objectId] isEqualToString:[PFUser currentUser].objectId]) {
                    NSLog(@"first event");
                } else if ([[match[kDDActivitySecondToUserKey] objectId] isEqualToString:[PFUser currentUser].objectId]) {
                    NSLog(@"second event");
                }
            }
        } 
    }
}];

解析PFUser currentUser查询键

1 个答案: