Question

我的数据库看起来像这样

tickets table
-------------
ticket_id
title
description
department_id
status_id
priority_id
assignee_id
creator_id

departments table
------------------
dep_id
dep_name

status table
------------
status_id
status_name

priority table
---------------
pr_id
pr_name

users table
-----------
u_id
username
password
salt
email
firstName
lastName
department_id
userlevel_id

userlevels table
-----------------
ul_id
ul_name

我需要在给定asignee id的情况下加载所有票证。我的查询看起来像这样

SQLQuery q = q.createSQLQuery("SELECT t.*,d.*,s.*,p.*,u.*,a.* FROM tickets t, departments d, status s, priority p, users u, attachments a WHERE t.department_id=d.dep_id AND t.status_id=s.stat_id AND t.priority_id=p.pr_id AND t.assignee_id=u.u_id AND t.creator_id=u.u_id AND t.tick_id=a.ticket_id AND assignee_id=?");

    q.setInt(0, some_valid_assignee_id);
    List<Object> result = q.list();

但是它返回了一个空对象列表。任何人都可以指出我正确的方向，谢谢!!

Answer 1

您应该使用正确的连接语法。。。使查询更易于阅读和编写。

但是，我猜测问题是：

t.assignee_id = u.u_id AND t.creator_id = u.u_id

那就是假设

t.assignee_id = t.creator_id

也许这在您的数据中永远不会发生。

Answer 2

在您的查询中，您有AND t.assignee_id = u.u_id和AND t.creator_id = u.u_id。返回任何记录的唯一方法是assignee_id和creator_id是否相同。我认为你真正需要做的是两次链接到users表：

SELECT t.*, d.*, s.*, p.*, u1.*, u2.*, a.* 
FROM tickets t
  INNER JOIN departments d ON t.department_id = d.dep_id 
  INNER JOIN status s ON t.status_id = s.stat_id 
  INNER JOIN priority p ON t.priority_id = p.pr_id 
  INNER JOIN users u1 ON t.assignee_id = u.u_id 
  INNER JOIN users u2 ON t.creator_id = u.u_id 
  INNER JOIN attachments a ON t.tick_id = a.ticket_id 
WHERE assignee_id = ?

复杂的sql查询返回空结果

2 个答案: