Question

我需要将包含我网站上模型视图链接的字段添加到django管理视图中。当我向list_display添加字段名称并定义用于呈现此URL的方法时：

class SetAdmin(admin.ModelAdmin):
    list_display = ['many other fields', 'show_set_url']

    def show_set_url(self, obj):
            return '<a href="#">Set</a>' # render depends on other fields

它显示在django admin中的Sets列表中，但不是以模型形式显示。如何修复此问题并在django admin中添加指向“设置表单”的链接？

我也试过为这个模型创建自定义表单：

from core.models import Set
from django import forms

class SetAdminForm(forms.Form):
    class Meta:
        model = Set

    def __init__(self, *args, **kwargs):
        super(SetAdminForm, self).__init__(*args, **kwargs)
        self.fields['foo'] = forms.IntegerField(label=u"Link")

但现在形式上有明显效果。

Answer 1

您可以通过覆盖ModelAdmin来完成您尝试的操作，但您还需要覆盖ModelAdmin.get_fieldsets。 This回答可能会帮到你。链接中的OP也存在类似的问题。

修改：如果您不想要可编辑字段，可以尝试覆盖ModelAdmin.get_readonly_fields。同时检查here是否有更多要覆盖的属性。

Answer 2

您可以使用表单元类创建动态字段和字段集。示例代码如下。根据您的要求添加循环逻辑。

class CustomAdminFormMetaClass(ModelFormMetaclass):
    """
    Metaclass for custom admin form with dynamic field
    """
    def __new__(cls, name, bases, attrs):
        for field in myloop: #add logic to get the fields
            attrs[field] = forms.CharField(max_length=30) #add logic to the form field
        return super(CustomAdminFormMetaClass, cls).__new__(cls, name, bases, attrs)


class CustomAdminForm(six.with_metaclass(CustomAdminFormMetaClass, forms.ModelForm)):
    """
    Custom admin form
    """

    class Meta:
        model = ModelName
        fields = "__all__" 


class CustomAdmin(admin.ModelAdmin):
    """
    Custom admin 
    """

    fieldsets = None
    form = CustomAdminForm

    def get_fieldsets(self, request, obj=None):
        """
        Different fieldset for the admin form
        """
        self.fieldsets = self.dynamic_fieldset(). #add logic to add the dynamic fieldset with fields
        return super(CustomAdmin, self).get_fieldsets(request, obj)

    def dynamic_fieldset(self):
        """
        get the dynamic field sets
        """
        fieldsets = []
        for group in get_field_set_groups: #logic to get the field set group
            fields = []
            for field in get_group_fields: #logic to get the group fields
                fields.append(field)

            fieldset_values = {"fields": tuple(fields), "classes": ['collapse']}
            fieldsets.append((group, fieldset_values))

        fieldsets = tuple(fieldsets)

        return fieldsets

Answer 3

我在Django 1.9中为内联模型解决了所有这些问题。

这是一个为我完成动态字段的代码片段。在这个例子中，我假设你已经有一个名为ProductVariant的模态，它包含一个名为Product的模型的外键关系：

class ProductVariantForm(forms.ModelForm):
  pass

class ProductVariantInline(admin.TabularInline):
  model = ProductVariant
  extra = 0

  def get_formset(self, request, obj=None, **kwargs):
    types = ( (0, 'Dogs'), (1, 'Cats'))
        #Break this line appart to add your own dict of form fields.
        #Also a handy not is you have an instance of the parent object in obj
    ProductVariantInline.form = type( 'ProductVariantFormAlt', (ProductVariantForm, ), { 'fancy_select': forms.ChoiceField(label="Animals",choices=types)})
    formset = super( ProductVariantInline, self).get_formset( request, obj, **kwargs)
    return formset

class ProductAdmin(admin.ModelAdmin):
  inlines = (ProductVariantInline, )

我的具体用例是ProductVariant有多对多的关系，只能根据条目的业务逻辑分组进行有限的选择。因此我需要在内联中自定义动态字段。

Answer 4

您必须将其添加到readonly_fields列表。

class SetAdmin(admin.ModelAdmin):
    list_display = ['many other fields', 'show_set_url']
    readonly_fields = ['show_set_url']

    def show_set_url(self, obj):
            return '<a href="#">Set</a>' # render depends on other fields

Relevant documentation.

Answer 5

对@santhoshnsscoe表示敬意，在Django-2.2.3中用于实现此目标的最少代码如下：

from django.forms.models import BaseInlineFormSet, ModelFormMetaclass


class MyModelFormMetaclass(ModelFormMetaclass):
    def __new__(cls, name, bases, attrs):
        for field in ['test_1', 'test_2', 'test_3']:
            attrs[field] = forms.CharField(max_length=30)
        return super().__new__(cls, name, bases, attrs)


class MyModelForm(forms.ModelForm, metaclass=MyModelFormMetaclass):
    class Meta:
        model = MyModel
        fields = '__all__'


class MyModelAdmin(admin.modelAdmin):
    form = MyModelForm

将动态字段添加到django管理模型表单

5 个答案: