Question

我要做的是以5 - DONE的增量打印结果。然后，只打印循环的最后一行。例如：如果z = 26，则打印z @ 5,10,15,20,25的结果。然后用z @ 26打印。我卡住了，无法解决。

for (int i = 1; i <= z; i++) {
    b = b + (b * y) + x + w;

    if (i % 5 == 0)
        //input 1
        System.out.println("In " + i + " years, IRA value: " + b);          

    //input 2 - value of IRA when retirement is reached
    System.out.println();

Answer 1

我不知道初始值为b，x，w和y的原因是什么，所以我只是以某种方式初始化它们。

但我认为你想要这样的事情：

public class HelloWorld{

     public static void main(String []args){

        int z = 26;
        int b = 0;
        int x = 1;
        int w = 2;
        int y = 1;

        for (int i = 1;i<=z;i++) {
            b = b+(b*y)+x+w;
            if (i % 5 == 0)
                System.out.println("In " + i + " years, IRA value: " + b);          
        }

        System.out.print(z);
     }
}

输出：

In 5 years, IRA value: 93
In 10 years, IRA value: 3069
In 15 years, IRA value: 98301
In 20 years, IRA value: 3145725
In 25 years, IRA value: 100663293
26

Answer 2

将您的条件更改为

if(i%5==0 || i==z)

Answer 3

在if中添加或（|| i == z）将完成工作

for (int i = 1;i<=z;i++) {
    b = b+(b*y)+x+w;
    if (i%5==0 || i==z)

    //input 1
    System.out.println("In " + i + " years, IRA value: " + b);          

    //input 2 - value of IRA when retirement is reached
    System.out.println();

    //end
}

打印循环的最后一行

3 个答案: