从同一个表中的不同列计算相同的值

Question

我的表包含一些列，其中两列可以包含相同的值。 我的要求是，如果其中一个列包含值超过6次或两者都可以组合具有大于6次，那么它将被输出。

REF     NONREF
--------------
7112    6162

7112    6162

7112    6162

7112    6162

7112    6162

7112    6162

6162    6237

7112    6237

Output should be ::
-------------------
7112

6162

如上所述，

          REF having '7172' (7 times)
          NONREF having '6162' (6 times) + REF having '6162' (1 time) = (7 times)

我尝试了下面的查询，但我知道它不符合要求

Select REF, count(*) from RDF_LINK
GROUP BY REF
Having count(*) > 6
UNION
Select NON, count(*) from RDF_LINK
GROUP BY NONREF
Having count(*) > 6

请帮助

Answer 1

首先将两列合并为一个列表：

SELECT Ref AS Value FROM RDF_Link
UNION ALL
SELECT Non          FROM RDF_Link

用作分组的源表：

SELECT Value, COUNT(*)
FROM (SELECT Ref AS Value FROM RDF_Link
      UNION ALL
      SELECT Non          FROM RDF_Link)
GROUP BY Value
HAVING COUNT(*) > 6

Answer 2

这也可以帮助你..

DECLARE @TAB TABLE (REF INT, NONREF INT)
INSERT INTO @TAB 
VALUES  (7112,6162),(7112,6162),(7112,6162),
        (7112,6162),(7112,6162),(7112,6162),
        (6162,6237),(7112,6237)
--SELECT * FROM @TAB

SELECT REF,
        COUNT(*) [COUNT] 
FROM    @TAB GROUP BY REF HAVING COUNT(*) > 6
UNION ALL
SELECT  NR.NONREF,
        NR.COUNT + R.COUNT [COUNT]
FROM    (SELECT NONREF,COUNT(*) [COUNT] FROM @TAB GROUP BY NONREF) NR
JOIN    (SELECT REF,COUNT(*) [COUNT] FROM @TAB GROUP BY REF) R ON NR.NONREF = R.REF
WHERE   (NR.COUNT + R.COUNT) > 6

<强>结果。