Question

问题在于，当我从http调用的控制器内部的导出函数调用记录器时，它只适用于本地策略，松弛和哨兵永远不会得到通知。

记录器设置类似于：

server.js

//...
winston = require('winston'),
Sentry = require('winston-sentry'),
slack = require('winston-slack').Slack,
winstonMongodb = require('winston-mongodb').MongoDB;

global.log = new (winston.Logger)({
    transports: [
        new (winston.transports.Console)({
            handleExceptions: true,
            prettyPrint: true,
            colorize: true,
        }),
        new (winston.transports.File)({ 
            filename: 'logs.log', 
            json: true,
            handleExceptions: true 
        }),
        new Sentry({
            dsn: "XXXXXXXXXXXXXXXXXXXXXXXXXX",
            patchGlobal: true,
        }),
        new slack({
            domain: "XXXXXXXXXXXXXXXXXXXXXXXXXX",
            apiToken: "XXXXXXXXXXXXXXXXXXXXXXXXXX",
            channel: "#XXXXXXXXXXXXXXXXXXXXXXXXXX",
            username: "XXXXXXXXXXXXXXXXXXXXXXXXXX",
            handleExceptions : true
        }),
        new(winston.transports.MongoDB)({
            dbUri: 'mongodb://XXXXXX:XXXXXXXX@XXXXXX.mongohq.com:XXXXXX/XXXXXX'
        })
    ],
}); 
//...

（我没有看到使用全局var的例子，如果它不是一个好主意让我知道，但是像这样它可以在所有文件中使用而无需导入。）

测试控制器：

test.js

//...
//called on server starts
log.info('test') //works with all transports

//called later by an HTTP request
exports.test = function(req, res, next){
    log.info('test') //only works with local transports (console and file)
}
//...

Answer 1

应尽可能避免使用全局变量，因为在这种情况下。您可以使用单例而不是使用全局“日志”，如下所示：

var winston = require('winston');

var LoggerSingle = (function () {       
    var instance = null;    

    function Logger () {};

    Logger.prototype = new (winston.Logger)({
                                transports: [...]
    });

    return {
        getInstance: function () {
            if (instance === null)
                instance = new Logger();
            return instance;
        }
    };      
})();       

exports.single = function () {
    return LoggerSingle.getInstance();
};

使用winstonjs与外部传输

1 个答案: