Question

我在UIWebView的实施中遇到了一个问题，即我必须在所有传出的网址请求中添加?app=1。就是当我在LoadRequest中使用http://google.com进行webView时，它应该将其转换为http://google.com?app=1 ...同样如果它是http://google.com/index.php那么它应该将其更改为http://google.com/index.php?app=1

我已经完成了this但是无法获得解决方案..

任何帮助都会很棒..

提前致谢

Answer 1

我认为你需要类似下面的内容

-(BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType{


    NSString *url=request.URL.absoluteString;

    NSRange extraParam=[url rangeOfString:@"app=1"];
    if(extraParam.location == NSNotFound){
        url=[url stringByAppendingString:@"?app=1"];

        NSURLRequest *newRequest=[NSURLRequest requestWithURL:[NSURL URLWithString:url]];
        [webView loadRequest:newRequest];
    }

  return YES;

}

虽然以上代码未经过测试，但请尝试使用，如果有效的话。

注意 - 这只是一个想法，而不是解决方案。

干杯。

Answer 2

如果您只想将app=1添加到初始请求中，然后再将其传递给loadRequest:，那么只需执行

// Based on we don't know what is after http://www.google.com
// there could be other parameters that we aren't aware of.
NSString *urlStr = @"http://www.google.com....";

// Lets search for '?' to see if there are any parameters set already
if([urlStr rangeOfString:@"?"].location == NSNotFound) {
    // There are no parameters already set so we are good and we can just add ours.
    urlStr = [urlStr stringByAppendingString:@"?app=1"];
} else {
    // The request already has some parameters so we want to be adding ours as an additional param
    urlStr = [urlStr stringByAppendingString:@"&app=1"];
}

// Now that we have added our parameter to the request string we can make create the request.
NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:urlStr]];
[webView loadRequest:request];

如果您想将其附加到每个请求，请尝试在webView:shouldStartLoadWithRequest:navigationType:中执行上述操作（以及一些小修改），如下所示

- (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType 
{
    NSString *urlRequestStr =  [[request URL] absoluteString];
    // We need to make sure that we haven't already been passed a request with app=1 on it.
    if([urlRequestStr rangeOfString:@"app=1"].location == NSNotFound) {
        // Lets search for '?' to see if there are any parameters set already
        if([urlRequestStr rangeOfString:@"?"].location == NSNotFound) {
            // There are no parameters already set so we are good and we can just add ours.
            urlRequestStr = [urlRequestStr stringByAppendingString:@"?app=1"];
        } else {
            // The request already has some parameters so we want to be adding ours as an additional param
            urlRequestStr = [urlRequestStr stringByAppendingString:@"&app=1"];
        }

        // Now that we have added our parameter to the request string we can make create the request.
        NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:urlRequestStr]];
        [webView loadRequest:request];
    }

    // Continue as normal
    return YES;
}

如果有人认为适合对此进行downvote，我会注意到这是经过测试的代码并且可以按照用户的要求运行。因此，如果您认为适合downvote，请留下您认为这值得投票的原因

UIWebView始终在url问题中添加参数

2 个答案: