RegExp替换不以某些符号开头的单词

Question

我可以这样做吗？

...blah-blah...AA_word.......blah-blah...AB_word......word........Nword....

我只需要替换那些不以“AB_”开头的单词出现，所以看起来像这样：

...blah-blah...AA_XXXX.......blah-blah...AB_word......XXXX........NXXXX....

这可能吗？我或多或少熟悉正则表达式，但仍然无法找到如何做到这一点。编程语言无关紧要 - php，js或c＃，无论

Answer 1

搜索：(?<!AB_)word
并替换为：XXXX

perl实现：

my $str = "...blah-blah...AA_word.......blah-blah...AB_word......word........Nword....";
$str =~ s/(?<!AB_)word/XXXX/g;
say $str;

<强>输出：

...blah-blah...AA_XXXX.......blah-blah...AB_word......XXXX........NXXXX....

使用php：

$str = "...blah-blah...AA_word.......blah-blah...AB_word......word........Nword....";
$str = preg_replace('/(?<!AB_)word/', 'XXXX', $str);
echo "$str\n";

Answer 2

在JS中：

var s = "...blah-blah...AA_word.......blah-blah...AB_word......word........Nword...."

s.replace("AB_word", "????").replace(/word/g, "XXXX").replace("????", "AB_word")
// results in 
// ...blah-blah...AA_XXXX.......blah-blah...AB_word......XXXX........NXXXX....

HTH