Question

我有一个文本文件如下

http://url.com/r/GFDGDFG
http://url.com/r/A32512F
http://url.com/r/AWDRE25
http://url.com/r/AGBFD35
http://url.com/r/NFG4622

有没有办法使用python（试图在我的linux盒子上获取一些简单的脚本）抓取每个URL（加载它）并获取最终的URL？每个网址/链接都是重定向，我想在重定向后获取网址。

Answer 1

import requests

urls = '''http://url.com/r/GFDGDFG
http://url.com/r/A32512F
http://url.com/r/AWDRE25
http://url.com/r/AGBFD35
http://url.com/r/NFG4622'''

for x in urls.splitlines():
    r = requests.get(x)
    print x, '=>', r.url

结果：

http://url.com/r/GFDGDFG => http://lyrics.url.com
http://url.com/r/A32512F => http://lyrics.url.com
http://url.com/r/AWDRE25 => http://lyrics.url.com
http://url.com/r/AGBFD35 => http://lyrics.url.com
http://url.com/r/NFG4622 => http://lyrics.url.com

抓取网址文件以在重定向后获取最终目标网址？

1 个答案: