Question

我需要将以下curl命令转换为java命令。

$curl_handle = curl_init ();

curl_setopt ($curl_handle, CURLOPT_URL,$url);`enter code here`
curl_setopt ($curl_handle, CURLOPT_FOLLOWLOCATION, 1);
curl_setopt ($curl_handle, CURLOPT_RETURNTRANSFER, 1);
curl_setopt ($curl_handle, CURLOPT_SSL_VERIFYPEER, 0);
curl_setopt ($curl_handle, CURLOPT_POST, 1);
curl_setopt ($curl_handle, CURLOPT_POSTFIELDS, $postfields);

//echo $postfields;

$curl_result = curl_exec ($curl_handle) or die ("There has been a CURL_EXEC error");

Answer 1

Http(s)UrlConnection可能是您的首选武器：

public String sendData() throws IOException {
    // curl_init and url
    URL url = new URL("http://some.host.com/somewhere/to/");
    HttpURLConnection con = (HttpURLConnection) url.openConnection();

    //  CURLOPT_POST
    con.setRequestMethod("POST");

    // CURLOPT_FOLLOWLOCATION
    con.setInstanceFollowRedirects(true);

    String postData = "my_data_for_posting";
    con.setRequestProperty("Content-length", String.valueOf(postData.length()));

    con.setDoOutput(true);
    con.setDoInput(true);

    DataOutputStream output = new DataOutputStream(con.getOutputStream());
    output.writeBytes(postData);
    output.close();

    // "Post data send ... waiting for reply");
    int code = con.getResponseCode(); // 200 = HTTP_OK
    System.out.println("Response    (Code):" + code);
    System.out.println("Response (Message):" + con.getResponseMessage());

    // read the response
    DataInputStream input = new DataInputStream(con.getInputStream());
    int c;
    StringBuilder resultBuf = new StringBuilder();
    while ( (c = input.read()) != -1) {
        resultBuf.append((char) c);
    }
    input.close();

    return resultBuf.toString();
}

我不太确定HTTPS_VERIFYPEER-thing，但这可能会给你一个起点。

Answer 2

查看java.net.URL和java.net.URLConnection库。

URL url = new URL("yourUrl.com");

然后使用一个InputStreamReader＆amp;的BufferedReader。

Oracles示例中的更多信息：http://docs.oracle.com/javase/tutorial/networking/urls/readingWriting.html

这也可能有所帮助：How to use cURL in Java?

什么相当于在java中跟随curl命令

2 个答案: