Question

我需要为一个名为try ..的表创建一个触发器，它会在输入到表中之后执行..（我使用的是phpmyadmin mysql）但我在创建它时遇到#1064错误。我的触发器包含

BEGIN
DECLARE aa decimal(4,3);
DECLARE bb decimal(4,3);
DECLARE cc decimal(4,3);
DECLARE cur1 CURSOR FOR SELECT a,b,c FROM site;
OPEN cur1;
FETCH NEXT FROM cur1 into aa,bb,cc;
WHILE FETCH_STATUS=0 DO
PRINT aa;
END WHILE;
END

它显示像这样的错误

 MySQL said: #1064 - You have an error in your SQL syntax; 
check the manual that corresponds to your MySQL server version 
for the right syntax to use near 'aa; END WHILE; END' at line 9

我是新手触发......帮助我......谢谢

Answer 1

尝试将while循环更改为

WHILE FETCH_STATUS=0 DO
//print here
END WHILE;

如此链接中所述

http://dev.mysql.com/doc/refman/5.7/en/while.html

另外请参阅有关mysql打印功能的这篇文章

How can I simulate a print statement in MySQL?

创建触发器时在mysql-＃1064错误中收到错误

1 个答案: