Loopj AsynHttpClient发布请求响应

Question

Loopj AsynHttpClient

ASP.Net

我正在尝试连接到ASP.NET WebApp。
OnSuccess回调，我想阅读网页并从网页上获取文本和数据。我怎样才能得到它或如何将其解析为JSON或XML？ 我通过将params发布到登录页面成功连接到该站点。现在我想读取重定向的网页。 以及如何保存cookie或缓存，以便在运行Android APP时自动登录。

client.get("https://uogis.uog.edu.pk/LandingPage.aspx", new AsyncHttpResponseHandler(){

                @Override
                public void onFailure(int arg0, Header[] arg1,
                        byte[] arg2, Throwable arg3) {
                    // TODO Auto-generated method stub

                }

                @Override
                public void onSuccess(int arg0, Header[] arg1,
                        byte[] arg2) {
                    // TODO Auto-generated method stub
                    mTextView.setText("In Landing Page now");

                }
                @Override
                public void onFinish() {
                    params.put("TextBox1","Home");
                    client.get("https://uogis.uog.edu.pk/ControlPanel.aspx",new AsyncHttpResponseHandler(){

                        @Override
                        public void onFailure(int arg0,
                                Header[] arg1, byte[] arg2,
                                Throwable arg3) {
                            // TODO Auto-generated method stub

                        }

                        @Override
                        public void onSuccess(int arg0,
                                Header[] arg1, byte[] arg2) {
                            // TODO Auto-generated method stub

                            mTextView.setText("In Control Panel\n"+ "ResponseCode "+arg0+ "\n" );
                        }});

                }
            });