这是我第一次发帖，因为我非常喜欢这个编程任务。本章我们开始学习结构。过去两周我们学习了数组和函数，因此作业试图将它们联系在一起。我想要做的是将这个结构数组传递给函数作为引用而不是元素。我的思维过程是大多数这些函数都没有返回任何内容，所以我希望在其中更新我的数组。我的问题是，我一直收到“getInput参数1的不兼容类型”的错误。
据我所知，我的语法是正确的。我概述了我的main函数之外的结构，我定义了一个emp变量，指定了一个从常量等派生的数组。我的函数应该没问题。这个程序在我最后一次分配时使用了各个数组，这次我删除了数组并替换了一个结构。我完全失去了吗？我只是试图通过这个第一个错误，如果有人能指出我正确的方向？
#include <stdio.h>
//Structures
struct employee {
long int id_number;
float wage;
float hours;
float overtime;
float gross;
};
//Constants
#define NUM_EMPL 5
#define OVERTIME_RATE 1.5f
#define WORK_WEEK 40.0f
//Prototypes
void getInput (struct employee input, int size);
float overtime (struct employee input);
void gross_pay (struct employee input, float work, float ot_rate, int size);
void output (struct employee input, int size);
int main () {
struct employee emp[NUM_EMPL] = {
{98401, 10.60},
{526488, 9.75},
{765349, 10.50},
{34645, 12.25},
{127615, 8.35}
};
int count;
getInput (emp, NUM_EMPL);
for (count = 0; count < NUM_EMPL; count++) {
//if overtime rate applies, function 'overtime' is called
if (emp.hours[count] > WORK_WEEK) {
//function overtime takes specific elements of array and two constants as arguments
emp.overtime[count] = overtime(emp, WORK_WEEK);
}
//if above does not apply, ot hours are set to 0
else {
emp.overtime[count] = 0.0;
}
}
//function called to calculate gross for each employee
gross_pay (emp, WORK_WEEK, OVERTIME_RATE, NUM_EMPL);
//function called to display output with proper header and formatting
output(emp, NUM_EMPL);
return (0);
}
//**************************************************************/
// Function: getInput
//
// Purpose: Obtains input from user, the number of hours worked
// per employee and stores the results in an array that is
// passed back to the calling program by reference.
//
// Parameters: emp_num - Array of employee clock numbers.
// hrs - Array of number of hours worked by an employee
// size - Number of employees to process */
//
// Returns: Nothing (call by refernce)
//
//**************************************************************/
void getInput (struct employee input, int size) //(long emp_num[], float emp_hrs[], int size)
{
int count; /* loop counter */
/* Get Hours for each employee */
for (count = 0; count < size; ++count)
{
printf("\nEnter hours worked by emp # %06li: ", input.id_number[count]);
scanf ("%f", &input.hours[count]);
}
printf("\n\n");
}
//**************************************************************/
// Function: overtime
//
// Purpose: Figures out amount of overtime hours worked by
//subtracting 'work' from emp hrs.
//
// Parameters: emp_hrs - Array of hours worked by employees
// work - standard hours of work before OT
// Returns: float ot_hours
//
//**************************************************************/
float overtime (struct employee input, int size) //(float emp_hrs, float work)
{
return (input.hours - work);
}
//**************************************************************/
// Function: gross_pay
//
// Purpose: Function that determines gross pay of each employee by multiplying ot rate by wage rate by hours worked
//and adding this amount to work times wage rate.
//
// Parameters: emp_hrs - Array of hours worked by employee
// wage_rate - Array of hourly wages for employees
// ot_hours - overtime hours if worked
// work - standard hours of work before OT
// ot_rate - time and a half constant
// size - amount of employees to be tested
//
// Returns: float gross to array of gross
//
//**************************************************************/
void gross_pay (struct employee input, float work, float ot_rate, int size) //(float emp_hrs[], float gross[], float wage_rate[], float ot_hours[], float work, float ot_rate, int size)
{
int count; //loop counter
for (count = 0; count < size; count++) {
input.gross[count] = (ot_rate * input.wage[count] * input.overtime[count]) + ((input.hours[count] - input.overtime[count]) * input.wage[count]);
}
}
//**************************************************************/
// Function: output
//
// Purpose: Displays output of calculations in a neat,
// table. Incorporates suppressed 0's and proper line allignment.
//
// Parameters: clock_number - array of each employee
// wage_rate - hourly wages for employees
// hours - hours worked by employees
// ot - overtime hours worked by employees
// gross - gross amount made by each employee
//
// Returns: Nothing: Displays printf within function
//
//**************************************************************/
void output (struct employee input, int size) //(long clock_number[], float wage_rate[], float hours[], float ot[], float gross[], int size)
{
int counter;
printf("\n\n####################################################################\n");
printf("##RESULTS##RESULTS##RESULTS##RESULTS##RESULTS##RESULTS##RESULTS#####\n");
printf("####################################################################\n\n");
printf("-------------------------------------------------------\n");
printf(" Clock Number Wage Hours OT Gross\n");
printf("-------------------------------------------------------\n");
//employee data is displayed in a proper format
for (counter = 0; counter < size; counter++) {
printf(" %06li %-4.2f %-4.2f %-2.2f %-5.2f\n", input.id_number[counter], input.wage[counter], input.hours[counter], input.overtime[counter], input.gross[counter]);
}
}
答案 0 :(得分：1)
在声明和定义中执行此操作
void getInput (struct employee input[], int size);
float overtime (struct employee input[],int size);
void gross_pay (struct employee input[], float work, float ot_rate, int size);
void output (struct employee input[], int size);
您对函数overtime()的声明和定义不同。它们包含不同的参数。您还应该修复它。
答案 1 :(得分：0)
您的功能被定义为对单个员工进行操作，而不是对其中的一组进行操作。我将展示如何修复gross_pay，您需要对其他功能进行类似的修复。
void gross_pay (struct employee input[], float work, float ot_rate, int size)
{
int count; //loop counter
for (count = 0; count < size; count++) {
input[count].gross = (ot_rate * input[count].wage * input[count].overtime) + ((input[count].hours - input[count].overtime) * input[count].wage);
}
}
访问结构成员时，它是input[count].member，而不是input.member[count] - 如果成员是数组，则使用后者，而不是作为数组中结构的元素。