Question

我希望我的查询返回表中的行，其中列首先包含特定值

所以我给出了这样的查询：

SELECT IDName
  FROM Type_ofID_tbl
 WHERE deleted = 0
 ORDER BY(IDName ='Emirates ID'), IDName

但显示错误

＆＃39; =＆＃39;。

附近的语法不正确

Answer 1

(IDName ='Emirates ID')条款中不需要ORDER BY;它应该是这样的

 SELECT IDName
   FROM Type_ofID_tbl
  WHERE deleted = 0
  ORDER BY IDName ASC

如果您想订购具有IDName ='Emirates ID'

的列

 SELECT IDName
   FROM Type_ofID_tbl
  WHERE deleted = 0
    AND IDName = 'Emirates ID'
  ORDER BY IDName ASC

ORDER BY关键字默认按升序对记录进行排序。要按降序对记录进行排序，您可以使用DESC关键字。

Answer 2

试试这个

select IDName 
from Type_ofID_tbl 
where deleted=0 order by case when IDName ='Emirates ID' then 1 else 2 end

Answer 3

除非明确说明，否则SQL表排序是任意的。此外，您不能在order by子句中使用逻辑运算符。

我的建议是将其分为两个查询：

SELECT IDNAME FROM [TABLE]
WHERE DELETED = 0
AND IDNAME = 'EMIRATES ID'
UNION ALL
SELECT IDNAME FROM [TABLE]
WHERE DELETED = 0
AND IDNAME != 'EMIRATES ID'
OR IDNAME IS NULL

感谢。

返回具有特定值的行首先获得语法错误

3 个答案: