Question

自昨晚以来我一直坚持这件事，所以最后我决定问你们这个。

我该怎么做才能解决这个问题？有什么错误吗？请帮忙;我是PHP的新手。

<?php

$connection = mysql_connect($HOST,$USER,$PASS) Or Die ("Could not connect to the server");
mysql_select_db($DBNAME, $connection )Or Die ("Could not connect to the server");

error_reporting(0);

if ($_POST['Register']);{
  if($_POST['Username'] && $_POST['Password']);
  $username = mysql_real_escape_string($_POST['Username']);
  $password = mysql_real_escape_string(hash("sha512",$_POST['Password']));
  $name ='';
  if($_POST['Name']){
    $name = mysql_real_escape_string(strip_tags($_POST[name]));
  }
  $check = mysql_fetch_array(mysql_query("SELECT * FROM 'users' WHERE 'Username'='$username'"));
  if ($check != '0'){
    die("Uh Oh! That Username has already taken! Try <i>$username" . rand (1,50) . "</i> instead! <a href='register.php'>&larr; Back </a>" );
  }
  if (!ctype_alnum($username)){
    die("Uh hum ! Your username conatins special characters unfortunately they are not permitted ! Only letters and numbers are allowed! <a href='register.php'>&larr; Back </a>");
  }
  if (strlen($username) >20){
    die("Username Cannot contain more than 20 characters <a href='register.php'>&larr; Back </a>");
  }
  $salt = hash("sha512", rand() .rand(). rand());
  mysql_query("INSERT INTO 'users' ('Username','Password','Name','Salt') VALUES('$username','$password','$name','$salt')");
  set_cookie("c_user", hash("sha512",$username),time() + 24 * 60 * 60, "/" );
  set_cookie("c_salt", $salt, $time () + 24 * 60 * 60, "/");
  die ("Congrts ! you are now ready to use Hack With Nick! You are now logged in !");
}

?>

<body style='font-family: sans-serif,verdana;'>
 <div style='width: 80%; padding: 5px 15px 5px ; border: 1px solid #e3e3e3; background-color: #fff; color:000 ; margin-left:auto; margin-right:auto;'>
  <h1>Register</h1>
  <br />
   <form action='' method='post' >
    <table>
     <tr>
      <td>
      <b>Username:</b>
      </td>
      <td>
       <input type='text' name='username' style='padding: 4px;' />
      </td>
     </tr>
     <tr>
      <td>
       <b>Password:</b>
      </td>
      <td>
      <input type='password' name='password' style='padding:4px;' />
      </td>
     </tr>
     <tr>
      <td>
       <b>Name:</b>
      </td>
      <td>
       <input type='text' name='name' style='padding:4px;' />
      </td>
     </tr>
     <tr>
      <td>
       <input type='submit' name='register' value='Register' />
      <td>
     </tr>
    </table>
  </form>
 </div>
</body>

Answer 1

首先，如果启用错误报告会更好。

error_reporting(E_ALL);
ini_set('display_errors','1');

其次，您的输入名称都是较低的，并且您在名称字段中缺少引号，因此您的if语句没有任何支撑使它们无用。同样如上面提到的Iserni：您的SQL代码包含错误，例如用户，而不是＆＃39;用户＆＃39; ，如果您不是$time正在尝试使用php的自己的功能，它是time()。

if (isset($_POST['register'])){
  if(!empty($_POST['username']) && !empty($_POST['password'])){
      $username = mysql_real_escape_string($_POST['username']);
      $password = mysql_real_escape_string(hash("sha512",$_POST['password']));
      $name ='';
      if(isset($_POST['name'])){
        $name = mysql_real_escape_string(strip_tags($_POST['name']));
      }
      $check = mysql_query("SELECT * FROM users WHERE 'Username'='$username'");
      if (mysql_num_rows($check) != 0){
        die("Uh Oh! That Username has already taken! Try <i>$username" . rand (1,50) . "</i> instead! <a href='register.php'>&larr; Back </a>" );
      }
      if (!ctype_alnum($username)){
        die("Uh hum ! Your username conatins special characters unfortunately they are not permitted ! Only letters and numbers are allowed! <a href='register.php'>&larr; Back </a>");
      }
      if (strlen($username) >20){
        die("Username Cannot contain more than 20 characters <a href='register.php'>&larr; Back </a>");
      }
      $salt = hash("sha512", rand() .rand(). rand());
      mysql_query("INSERT INTO users ('Username','Password','Name','Salt') VALUES('$username','$password','$name','$salt')");
      set_cookie("c_user", hash("sha512",$username),time() + 24 * 60 * 60, "/" );
      set_cookie("c_salt", $salt, time() + 24 * 60 * 60, "/");
      die ("Congrts ! you are now ready to use Hack With Nick! You are now logged in !");
    }
}

PHP登录页面无法正常工作

1 个答案: