将查询结果插入codeigniter中的另一个查询

时间:2014-07-01 11:32:54

标签: php sql codeigniter

我需要插入查询结果作为另一个查询的输入 这是我尝试过的代码,请立即提供帮助 我需要从query1获取id并将其作为$ id

插入query2
class Get_db extends CI_Model{
    public function get_All(){
        $query1 = $this->db->query("SELECT name,id from companydetails");
        return $query->result();
    }

    public function getBranches(){
        $query2 = $this->db->query("SELECT branches.name FROM branches WHERE           branches.companyid=$id ");
        return $query2->result();
    }
}

我需要从query1获取id并将其作为$ id

插入query2

5 个答案:

答案 0 :(得分:1)

方法get_All()返回一个对象,因此您可以使用:

$resultQuery1 = get_All();

$output = array();

foreach($resultQuery1 as $q)
    $output[$q->id] = getBranches($q->id);

在getBranches方法中,您应该接受参数

public function getBranches($id) {...}

$ output变量是一个包含getBranches方法的所有结果的数组。

答案 1 :(得分:1)

试试这段代码:

    <?php 
$this->db->select('name,id')
    ->from('companydetails');
$qry = $this->db->get();
$res = $qry->result();

foreach($res as $val){
    $this->db->select('name')
        ->from('branches')
        ->where('companyid', $val->id);
    $qry2 = $this->db->get();
    $res2 = $qry->result();
}   

return $res2;

?>

$ res 数组是第一个查询的执行结果,该查询将作为第二个查询的输入

答案 2 :(得分:0)

这样做......

      public function get_All()
      {
                $this->db->select('name, id');
                $query = $this->db->get('companydetails');
                if ($query->num_rows () > 0)
                {

                         $result = $query->result();
                           foreach($result as $company)
                           {
                                    $company->branches = $this->getBranches($company->id);                                       
                           }

                          return $result;
                }
                else
                {
                    return false;
                }
      }

      public function getBranches($id)
      {
                $query = $this->db->get_where('branches', array('id' => $id));
                return $query->result();
      }

答案 3 :(得分:0)

可以在一个简单的功能中使用。使用 JOIN -

<?php
class Get_db extends CI_Model
{
   public function get_company_branches()
   {
      $this->db->select('companydetails.name','companydetails.id','branches.name');
      $this->db->from('companydetails');
      $this->db->join('branches', 'companydetails.id = branches.companyid');

      $query = $this->db->get();

      $result = array();
      if($query->num_rows() > 0)
          $result = $query->result_array();

      echo '<pre>'; print_r($result);    // Your expected result
   }
}


如果您不想使用加入并转到问题,请转到此处:


型号:

...
...
public function get_All()
{
    $this->db->select("id","name");
    $this->db->from("companydetails");

    $query = $this->db->get();
    return $query->result();
}

public function getBranches($id)
{
    $this->db->select("name");
    $this->db->from("branches");
    $this->db->where("companyid", $id)

    $query = $this->db->get();
    return $query->result();
}


控制器:

...
...
public function somename()
{
    $companies = $this->get_db->get_All();

    $branches = array();
    foreach($companies as $company)
    {
       $branches[] = $this->get_db->getBranches($company->id);
    }

    echo '<pre>'; print_r($branches);   // Expected result
}

答案 4 :(得分:0)

控制器

 public function home(){
        $this->load->model('get_company_model');
        $this->load->view('view_header');
        $data['results'] = $this->get_company_model->get_all();

        $this->load->view('view_nav',$data);
        $this->load->view('view_content');
        $this->load->view('view_footer');
    }

模型

 public function get_All(){
        $query = $this->db->query("SELECT name,id from companydetails");
        return $query->result();

    }
    public function get_branch($companyID){
        $query = $this->db->query("SELECT name,id from branches WHERE companyid='".$companyID."'");
        return $query->result();

    }

视图

<div>
        <ol class="tree">
    <li>
        <label for="folder1"><?=$row->name?></label> <input type="checkbox"  id="folder1" /> 
        <ol>
              <?php
                $myresult=$this->get_company_model->get_branch($row->id);
                foreach($myresult as $row2):
                  ?>  
            <li class="file"><a href="#"><?=$row2->name?></a></li>
            <?php
                 endforeach;
                ?>
</ol>
    </div>

    <?php
    endforeach;
    ?>