如何使用Spring Social从SecurityContextHolder获取用户的记录ID?

时间:2014-07-03 02:23:07

标签: spring spring-security

那么,如何从任何社交提供商的当前登录用户获取用户的ID? 我知道我可以构建一个自定义的SocialUser,就像我为User做的那样,但是在SocialUserDetails上没有getter的情况下我得到的方法只接受userDetails,而不是普通的" Person"实体。

public class SocialUsersDetailServiceImpl implements SocialUserDetailsService {


    private UserDetailsService service;

    public SocialUsersDetailServiceImpl(UserDetailsService service) {
        this.service = service;
    }

    @Override
    public CSocialUserDetails loadUserByUserId(String username) throws UsernameNotFoundException, DataAccessException {
        UserDetails userDetails = (UserDetails) service.loadUserByUsername(username);
        return new CustomSocialUser(userDetails.getUsername(), userDetails.getPassword(), userDetails.getAuthorities(), userDetails.getUserIdentifier()??);

    }
}

但是没有" .getUserIdentifier()"对于UserDetails的方法,有一些解决方法吗?

我为用户做的方式:

@Service
public class UserDetailsServiceImpl implements CUserDetailsService {

   @Resource
   private PersonRepository respository;

    @Override
    public CUserDetails loadUserByUsername(String username) throws UsernameNotFoundException {
        Person p = repository.findByUsername(username);
        return new CUser(p.getUsername(), p.getPassword(), p.grantedAuthorities(), p.getIdPerson());
    }
}

和CUser:

public class CUser extends User{


    private Number identifier;

    public CUser(String username, String password, Collection<? extends GrantedAuthority> authorities, Number identifier) {
        super(username, password, authorities);
        this.identifier = identifier;

    }


    public Number getUserIdentifier() {
        return identifier;
    }

}

0 个答案:

没有答案
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