Question

这是我的代码

$Meeting="4181211";
$EventID="Wanganui";
$Description="G Bristol & Sons (Bm75)";
$entities = array(' ', '%28', '%29');
$replacements = array('-',"(", ")");
echo str_replace($entities,$replacements, strtolower("https://www.ladbrokes.com.au/racing/greyhounds/".$Meeting."/".$EventID."-".$Description."/"));

输出就像

https://www.ladbrokes.com.au/racing/greyhounds/4181211/wanganui-g-bristol-&-sons-(bm75)/

这很好，但在我的其他情况下

$Meeting="4222658";
$EventID="Yonkers";
$Description="Yonkers Raceway F&M Clm Pce Ms";
$entities = array(' ', '%28', '%29');
$replacements = array('-',"(", ")");
echo str_replace($entities,$replacements, strtolower("https://www.ladbrokes.com.au/racing/greyhounds/".$Meeting."/".$EventID."-".$Description."/"));

输出类似于https://www.ladbrokes.com.au/racing/greyhounds/4222658/yonkers-yonkers-raceway-f&m-clm-pce-ms/

但这是一个问题，我希望我的输出像https://www.ladbrokes.com.au/racing/greyhounds/4222658/yonkers-yonkers-raceway-f-m-clm-pce-ms/

我只想查看描述是否没有空格（之前/之后）＆＃39;＆amp;＆＃39;然后它应该被替换为＆＃39; - ＆＃39;。例如，在f＆amp; m的情况下，我想要像f＆m;＆＃39;布里斯托尔＆amp; Sons就像Bristol-＆amp; -Sons一样很好，而且（）在输出中没有被％28和％29取代任何建议吗？

Answer 1

如果你想要做的只是在原始描述中用&替换-;只需在构建完整URL之前执行此操作：

$Description=preg_replace("/(\w)&(\w)/",'$1-$2',"Yonkers Raceway F&M Clm Pce Ms");
// => //www.ladbrokes.com.au/racing/greyhounds/4222658/yonkers-yonkers-raceway-f-m-clm-pce-ms/

和另一个案例，你得到：

$Description=preg_replace("/(\w)&(\w)/", "$1-$2", "G Bristol & Sons (Bm75)");
// => https://www.ladbrokes.com.au/racing/greyhounds/4222658/yonkers-g-bristol-&-sons-(bm75)/

PHP str_replace替换＆amp;字符' - '

1 个答案: