pivot用于多列的逗号分隔值

Question

我有一个如下查询，它给出了结果集，如图所示

SELECT  E1.Name,E1.AccountType ,
        STUFF(( SELECT DISTINCT ', ' + CAST(E2.AccountNumber as nvarchar(50))
                FROM    @temp AS e2 
                WHERE   e1.Name = e2.Name and e1.AccountType = e2.AccountType
                FOR XML PATH('')
            ), 1, 2, '') AS AccountNumber ,
          STUFF(( SELECT DISTINCT ', ' + CAST(E2.CustomerNumber as nvarchar(50))
                FROM    @temp AS e2 
                WHERE   e1.Name = e2.Name and e1.AccountType = e2.AccountType
                FOR XML PATH('')
            ), 1, 2, '')  AS CustomerNumber     

FROM    @temp AS e1 
GROUP BY Name,AccountType

现在我想透过这个结果集而不是三行，我的结果集只包含一行，每C,I,T AccountNumber个CustomerNumber三列。

我已经使用单个AccountNumber列编写了以下查询以进行数据透视，并且该工作对我有用，但我无法了解如何在此数据透视图中包含其他列CustomerNUmber？

这里是我为单列数据透视表写的查询结果集图像

SELECT  * from 
(
SELECT  E1.Name,E1.AccountType ,
        STUFF(( SELECT DISTINCT ', ' + CAST(E2.AccountNumber as nvarchar(50))
                FROM    @temp AS e2 
                WHERE   e1.Name = e2.Name and e1.AccountType = e2.AccountType
                FOR XML PATH('')
            ), 1, 2, '') AS AccountNumber   

FROM    @temp AS e1 
GROUP BY Name,AccountType
) as src 
PIVOT  (MAX(AccountNumber) FOR AccountType IN (C,I,T) )AS pvt

已编辑：

sqlfiddle link

Answer 1

-如果只希望将每个组及其对应的值连接在一起，则无需枢轴操作

SELECT *
FROM (
    SELECT E1.[Field_Type]
        ,STUFF((
                SELECT CASE 
                        WHEN E1.[Field_Type] = b.[Field_Type]
                            THEN ', ' + E2.COLUMN_NAME
                        END
                FROM [DB].[Schema].[Table1] b
                INNER JOIN INFORMATION_SCHEMA.COLUMNS E2
                    ON E2.COLUMN_NAME = b.COLUMN_NAME
                FOR XML PATH('')
                ), 1, 2, '') AS a
    FROM [DB].[Schema].[Table1] AS e1
    GROUP BY [Field_Type]
    ) AS src