C中类型'int *'和'long unsigned int'到二进制'operator *'错误的无效操作数

Question

所以我不断收到以下编译错误;

src/c/testHO.c: In function ‘int main(int, char**)’:
src/c/testHO.c:79:56: error: invalid operands of types ‘int*’ and ‘long unsigned int’ to       binary ‘operator*’
src/c/testHO.c:145:26: error: cannot convert ‘int*’ to ‘float*’ for argument ‘27’ to ‘void       hfmmcalc_(float*, float*, float*, float*, int*, int*, float*, float*, int*, double*, int*, int*, float*, float*, float*, float*, int*, int*, float*, float*, int*, int*, float*, int*, int*, float*, float*, float*, int*, int*)’

此错误与代码的以下部分有关

    int wkspSize = 32*(npart+NGRID)+1000;
    float* WKSP = (float*) malloc(wkspSize*sizeof(float));
    int hfmmInfoSize = 4;
    int* hfmmInfo = (int*) malloc(&hfmmInfoSize*sizeof(int));

我正在努力找到这个错误的确切位置。我已经尝试更改第27个参数（hffmInfoSize），以便它以float形式给出，我尝试将最后一行更改为float。我对C很新，所以它可能是一个简单的修复

Answer 1

你似乎有一个迷路& - 改变：

int* hfmmInfo = (int*) malloc(&hfmmInfoSize*sizeof(int));

为：

int* hfmmInfo = malloc(hfmmInfoSize*sizeof(int));

另请注意删除malloc调用结果的redundant (and potentially dangerous) cast。