Question

我正在分享我的SQL如果有人比这更好，请在这里发帖。

要在查询下方获得第一笔最高薪水：

select salary from employee order by salary desc limit 1;

要在查询下方获得第二高薪：

select salary from employee order by salary desc limit 1,1;

要在查询下方获得第三高薪：

select salary from employee order by salary desc limit 2,1;

Answer 1

您可以使用此查询获得前N个工资，其中N是第N个最高工资。

SELECT *
FROM Employee Emp1
WHERE (N) = (
               SELECT COUNT(DISTINCT(Emp2.Salary))
               FROM Employee Emp2
               WHERE Emp2.Salary >= Emp1.Salary
               )

Answer 2

你的代码很好......除了工资的倍数存在之外......即如果前10名工资是1000，那么最高薪水= 1000，前3名= 1000等等

使用分组...

select salary
from employee
GROUP BY salary
order by salary desc limit 1;

或不同的......

select DISTINCT(salary)
from employee
order by salary desc limit 1;

Answer 3

我会做以下事情：

SELECT TOP 1 FROM employee ORDER BY salary desc

获得第二高的

SELECT TOP 1 FROM employee ORDER BY salary DESC OFFSET 1

获得第三个

SELECT TOP 1 FROM employee ORDER BY salary DESC OFFSET 2

但是如果你打算在同一段代码中使用所有三个代码，我建议同时将它们全部3个，因为这会让你执行2个队列。我想建议一个对开的查询来获得前3名最高薪水

SELECT TOP 3 FROM employee ORDER BY salary DESC

Answer 4

为什么不使用像这样的查询

SELECT * FROM employee ORDER BY salary DESC LIMIT 3;

当你解析它时，你可以走到每一行。我认为使用LIMIT 3比使用TOP 3更好。推荐Here

如何从员工表中获得第一高或第二高或第三高薪

4 个答案: