Question

我正在尝试使用Hibernate实现软删除，但出于某种原因我的记录仍然被删除。有人介意看看。

public class SoftDeleteEventListener extends DefaultDeleteEventListener {

private static final long serialVersionUID = 1L;

@SuppressWarnings("rawtypes")
@Override
public void onDelete(DeleteEvent event, Set transientEntities) throws HibernateException {
    Object dbEntity = event.getObject();

    if (dbEntity instanceof Entity) 
    {
        ((Entity)dbEntity).setDeleted(true);
        ((Entity)dbEntity).setDeletedOn(new Date());

        EntityPersister persister = event.getSession().getEntityPersister( event.getEntityName(), dbEntity);
        EntityEntry entityEntry = event.getSession().getPersistenceContext().getEntry(dbEntity);

        cascadeBeforeDelete(event.getSession(), persister, dbEntity, entityEntry, transientEntities);
        cascadeAfterDelete(event.getSession(), persister, dbEntity, transientEntities);
    } else {
        super.onDelete(event, transientEntities);
    }
}

}

这就是我注册会话/听众的方式

Configuration configuration = new Configuration();
        configuration.configure();
        StandardServiceRegistryBuilder ssrb = new StandardServiceRegistryBuilder().applySettings(configuration.getProperties());
        sessionFactory = configuration.buildSessionFactory(ssrb.build());

        EventListenerRegistry registry = ((SessionFactoryImpl)sessionFactory).getServiceRegistry().getService(
        EventListenerRegistry.class);
        registry.getEventListenerGroup(EventType.DELETE).appendListener(new SoftDeleteEventListener());

Answer 1

为什么不依赖于SQLDelete覆盖，就像在this blog post中非常好地解释一样。

您定义了已删除的列

您使用

注释实体

@SQLDelete(sql="UPDATE customer SET deleted = true WHERE id = ?")

这比使用Hibernate Interceptor要简单得多。

我会尝试更简单的版本：

if (dbEntity instanceof Entity) 
{
    ((Entity)dbEntity).setDeleted(true);
    ((Entity)dbEntity).setDeletedOn(new Date());

    event.getSession().mergedbEntity
} else {
    super.onDelete(event, transientEntities);
}

Hibernate Soft Deletion仍然删除我的记录

1 个答案: