Question

* IDE：XCODE 6 beta3
*语言：Swift + Objective C

这是我的代码。

目标C代码

@implementation arrayTest
{
    NSMutableArray *mutableArray;
}
- (id) init {
    self = [super init];
    if(self) {
        mutableArray = [[NSMutableArray alloc] init];
    }
    return self;
}
- (NSMutableArray *) getArray {
    for(...; ...; ...) {
          ...
        NSString *cutFinal = xxx;
        [mutableArray addObject: cutFinal];
    }
    return mutableArray; // mutableArray = {2, 5, 10}
}

Swift Code

var target = arrayTest.getArray() // target = {2, 5, 10} 

for index in 1...10 {
    for targetIndex in 0..target.count {
        if index == target.objectAtIndex(targetIndex) as Int { 
            println("GET")
        } else {
            println(index)
        }
    }
}

我想要以下结果：

1 GET 3 4 GET 6 7 8 9 GET

但是，我的代码给了我错误

libswift_stdlib_core.dylib`swift_dynamicCastObjCClassUnconditional:
0x107e385b0:  pushq  %rbp
...(skip)
0x107e385e4:  leaq   0xa167(%rip), %rax        ; "Swift dynamic cast failed"
0x107e385eb:  movq   %rax, 0x6e9de(%rip)       ; gCRAnnotations + 8
0x107e385f2:  int3   
0x107e385f3:  nopw   %cs:(%rax,%rax)

if index == target.objectAtIndex(targetIndex-1) as Int { 
// target.objectAtIndex(0) = 2 -> but type is not integer

我认为此代码不完整。但我无法找到解决方案帮助我T T

我解决了问题!!!

我的目标C代码

NSString *cutFinal = xxx;
[mutableArray addObject: cutFinal];

修复

NSString *cutFinal = xxx;
NSNumber *add = [NSNumber numberWithInteger:[cutFinal intValue]];
[mutableArray addObject: add];

和我的Swift代码

 var target = arrayTest.getArray() as [Int]

Answer 1

我本可以充分利用Swift，写下这样的东西：

    for index in 1...10 {
        let array = target.filter{$0 == index}
        let value = array.count == 0 ? "\(index)" : "GET"
        println("\(value)")
    }

Swift动态演员失败了

1 个答案: