Question

我有一个包含这些列的表：

Id, Method, DateTime, time taken

实施例

1, Done,      2014-06-22 08:18:00.000, 2000
2, Not Done,  2014-06-23 04:15:00.000, 5000
3, Done,      2014-06-23 14:15:00.000, 6000

我希望将结果设置为＆＃34; DONE方法在上午8点到下午15点之间的每15分钟间隔内所花费的平均时间＆＃34;

请指导我如何继续这个，我不确定光标是否符合此要求。

Answer 1

我不完全确定这是否是你想要的，但这里是代码：

CREATE TABLE #Test(
id int IDENTITY(1,1) PRIMARY KEY,
Method nvarchar(50),
[Datetime] datetime,
timeTaken Bigint
)

CREATE TABLE #Result(
[Between] datetime,
[And] datetime,
[Avg] bigint)

INSERT INTO #Test (Method,Datetime,timeTaken)
VALUES(
'Done', '2014-06-22 08:18:00.000', 2000),
('Not Done', '2014-06-23 04:15:00.000', 5000),
('Done', '2014-06-23 14:15:00.000', 6000)

DECLARE @MaxTime datetime,@StartTime datetime,@Next datetime

SELECT @MaxTime = MAX([datetime]),
@StartTime = MIN([datetime])
FROM #TEST

WHILE @StartTime <= @MaxTime
BEGIN

SET @Next = (SELECT Dateadd(MINUTE,15,@StartTime))

INSERT INTO #Result
SELECT @StartTime AS [Between], @Next AS [And],AVG(timeTaken) AS [AVG]
FROM #Test 
WHERE [Datetime] Between @StartTime AND @Next
AND Method = 'Done'

SET @StartTime = @Next

END

SELECT * FROM #Result

DROP TABLE #Test
DROP TABLE #Result

您现在可以设置选择*从#result的位置，您可以在上午8点到下午3点之间说出如果这是你想要的，请告诉我

艾蒂安

Answer 2

您可以使用CTE生成季度列表。然后left join查找每季度的运行时间。 group by将允许您计算平均值。

在SQL Server 2012中，time类型可用，您可以：

; with  quarters as
        (
        select  cast('08:00' as time) as time
        union all
        select  dateadd(minute, 15, time)
        from    quarters
        where   time <= '14:30'
        )  
select  q.time
  ,       avg(rt.time_taken) as avg_time_taken
from    quarters q
left join
        RunTime rt
on      q.time <= cast(rt.dt as time)
        and cast(rt.dt as time) < dateadd(minute, 15, q.time)
        and method = 'Done'
group by
        q.time

Live example at SQL Fiddle.

对于SQL Server 2008R2和earler，您可以使用整数数学：

; with  quarters as
        (
        select  8*60 as min
        union all
        select  min + 15
        from    quarters
        where   min < 15*60
        )  
select  q.min / 60 as hour
,       q.min % 60 as minute
,       avg(rt.time_taken) as avg_time_taken
from    quarters q
left join
        (
        select  datepart(minute, dt) +
                60 * datepart(hour, dt) as min
        ,       time_taken
        from    RunTime
        where   method = 'Done'
        ) rt
on      q.min <= rt.min and rt.min < q.min + 15
group by
        q.min;

Live example at SQL Fiddle.

每季度平均时数

2 个答案: