通过匹配两个属性来删除查询

Question

CREATE OR REPLACE 
PROCEDURE deleteProcFood(id IN food_item.R_ID%TYPE,
item_name IN food_item.ITEM_NAME%TYPE)IS
BEGIN

DELETE FROM food_item
WHERE food_item.R_ID = id  AND
food_item.ITEM_NAME = item_name;

COMMIT;

END;
/

这是通过匹配两个属性值进行删除的过程，但它通过仅匹配R_ID来删除值。在这里，与AND之后的值匹配不起作用。如何解决这个问题？

Answer 1

检查是否有效：

CREATE OR REPLACE 
PROCEDURE deleteProcFood(PIN_ID IN food_item.R_ID%TYPE,
PIN_item_name IN food_item.ITEM_NAME%TYPE)IS
BEGIN

DELETE FROM food_item
WHERE food_item.R_ID = PIN_ID   AND
food_item.ITEM_NAME = PIN_item_name;

COMMIT;

END;
/

我怀疑ITEM_NAME = ITEM_NAME是否总是返回true。因此尝试更改参数变量名称。

Answer 2

优良作法是始终为所有内容添加别名，例如：

CREATE OR REPLACE 
PROCEDURE deleteProcFood(id IN food_item.R_ID%TYPE,
item_name IN food_item.ITEM_NAME%TYPE)IS
BEGIN

DELETE FROM food_item
WHERE food_item.R_ID = deleteProcFood.id  AND
food_item.ITEM_NAME = deleteProcFood.item_name;

COMMIT;

END;
/