Powershell:比较对象不比较嵌套对象

时间:2014-07-16 20:30:21

标签: json powershell comparison

或者我是如何停止担心并学会喜欢字符串集的

给出以下两个json字符串:

$jsonString1 = '{ "baz": "quuz", "cow": [ "moo", "CUD" ], "foo": "bar" }'
$jsonstring2 = '{ "baz": "quuz", "cow": [ "moo", "GRASS" ], "foo": "bar" }'

我希望得到它们所代表的对象的差异

<# First attempt: Convert each to an object, then compare normally #>
function Compare-Json {
    <# Make powershell objects from each string #>
    $obj1 = $jsonString1 | ConvertFrom-Json
    $obj2 = $jsonstring2 | ConvertFrom-Json

    Compare-Object $obj1 $obj2
}

PS E:\temp> Compare-Json

PS E:\temp> 

是的,根本就没有输出。

目前的解决方法是将json转换为对象,返回字符串,然后拆分字符串,最后比较每个集合

function Compare-Json {
    <# Convert to pretty json, then split to make a string array #>
    $obj1 = $($jsonString1 | ConvertFrom-Json | ConvertTo-Json) -split ([Environment]::NewLine)
    $obj2 = $($jsonstring2 | ConvertFrom-Json | ConvertTo-Json) -split ([Environment]::NewLine)

    Compare-Object $obj1 $obj2
}


PS E:\temp> Compare-Json

InputObject      SideIndicator                                               
-----------      -------------                                               
"GRASS"          =>                                                          
"CUD"            <=                                                          

PS E:\temp> 

是否有更简单的方法来深度比较两个对象?

1 个答案:

答案 0 :(得分:0)

不知道它是否更好,但是:

$jsonString1 = '{ "baz": "quuz", "cow": [ "moo", "CUD" ], "foo": "bar" }'
$jsonstring2 = '{ "baz": "quuz", "cow": [ "moo", "GRASS" ], "foo": "bar" }'

compare $jsonString1.split(',:[]{}') $jsonString2.split(',:[]{}')


InputObject                                          SideIndicator                                      
-----------                                          -------------                                      
 "GRASS"                                             =>                                                 
 "CUD"                                               <=