计算给定日期范围内的星期一数

时间:2008-10-29 20:20:28

标签: c# datetime date datediff

考虑到日期范围,我需要知道在该范围内有多少星期一(或星期二,星期三等)。

我目前正在使用C#。

15 个答案:

答案 0 :(得分:40)

试试这个:

static int CountDays(DayOfWeek day, DateTime start, DateTime end)
{
    TimeSpan ts = end - start;                       // Total duration
    int count = (int)Math.Floor(ts.TotalDays / 7);   // Number of whole weeks
    int remainder = (int)(ts.TotalDays % 7);         // Number of remaining days
    int sinceLastDay = (int)(end.DayOfWeek - day);   // Number of days since last [day]
    if (sinceLastDay < 0) sinceLastDay += 7;         // Adjust for negative days since last [day]

    // If the days in excess of an even week are greater than or equal to the number days since the last [day], then count this one, too.
    if (remainder >= sinceLastDay) count++;          

    return count;
}

答案 1 :(得分:20)

由于您使用的是C#,如果您使用的是C#3.0,则可以使用LINQ。

假设您有一个Array / List / IQueryable等包含DateTime类型的日期:

DateTime[] dates = { new DateTime(2008,10,6), new DateTime(2008,10,7)}; //etc....

var mondays = dates.Where(d => d.DayOfWeek == DayOfWeek.Monday); // = {10/6/2008}

添加了:

不确定你是否意味着将它们分组并计算它们,但这里也是如何在LINQ中做到这一点:

var datesgrouped = from d in dates
                   group d by d.DayOfWeek into grouped
                   select new { WeekDay = grouped.Key, Days = grouped };

foreach (var g in datesgrouped)
{
    Console.Write (String.Format("{0} : {1}", g.WeekDay,g.Days.Count());
}

答案 2 :(得分:17)

查看用于计算星期几的不同算法很有趣,而且@Gabe Hollombe指向WP关于这个主题是一个好主意(我记得大约二十年前在COBOL中实现Zeller's Congruence),但它当他们问到时间是什么的时候,就像把时钟的蓝图交给某人一样。

在C#中:

    private int CountMondays(DateTime startDate, DateTime endDate)
    {
        int mondayCount = 0;

        for (DateTime dt = startDate; dt < endDate; dt = dt.AddDays(1.0))
        {
            if (dt.DayOfWeek == DayOfWeek.Monday)
            {
                mondayCount++;
            }
        }

        return mondayCount;
    }

这当然不会评估“星期一”的结束日期,所以如果需要,请进行for循环评估

dt < endDate.AddDays(1.0)

答案 3 :(得分:5)

这是一些伪代码:

DifferenceInDays(Start, End) / 7   // Integer division discarding remainder
+ 1 if DayOfWeek(Start) <= DayImLookingFor
+ 1 if DayOfWeek(End)   >= DayImLookingFor
- 1

DifferenceInDays以天为单位返回End - StartDayOfWeek以整数形式返回星期几。 DayOfWeek使用的映射并不重要,只要它正在增加并与DayImLookingFor匹配。

请注意,此算法假定日期范围包含在内。如果End不应该是范围的一部分,则必须稍微调整算法。

转换为C#留给读者练习。

答案 4 :(得分:3)

任何特定语言,因此日期格式?

如果将日期表示为天数,那么两个值加上一(天)之差除以7就是答案的大部分。如果两个结束日期都是相关日期,请添加一个。

编辑:将'modulo 7'更正为'除以7' - 谢谢。那就是整数除法。

答案 5 :(得分:3)

我遇到了一种使用linq来解决这个问题的方法。

public static int NumberOfFridays(DateTime start, DateTime end) 
{ 
    return start.GetDaysInBetween(end, inclusive: true).Count(d => d.DayOfWeek == DayOfWeek.Friday); 
} 

希望有所帮助。

答案 6 :(得分:1)

添加尽可能少的数字,使第一天成为星期一。减去最小的数字,使最后一天成为星期一。计算天数之差并除以7。

答案 7 :(得分:1)

将日期转换为Julian Day Number,然后进行一些数学运算。由于星期一是零mod 7,你可以这样计算:

JD1=JulianDayOf(the_first_date)
JD2=JulianDayOf(the_second_date)
Round JD1 up to nearest multiple of 7
Round JD2 up to nearest multiple of 7
d = JD2-JD1
nMondays = (JD2-JD1+7)/7    # integer divide

答案 8 :(得分:1)

我今天也有同样的需求。我开始使用 cjm 函数,因为我不理解 JonB 函数,因为 Cyber​​herbalist 函数不是线性的。

我必须纠正

DifferenceInDays(Start, End) / 7   // Integer division discarding remainder
+ 1 if DayOfWeek(Start) <= DayImLookingFor
+ 1 if DayOfWeek(End)   >= DayImLookingFor
- 1

DifferenceInDays(Start, End) / 7   // Integer division discarding remainder
+ 1 if DayImLookingFor is between Start.Day and End.Day 

使用返回true的between函数,如果从开始日开始,我们首先在endDay之前遇到dayImLookingFor。

我通过计算从startDay到其他两天的天数来完成介于两者之间的功能:

private int CountDays(DateTime start, DateTime end, DayOfWeek selectedDay)
{
    if (start.Date > end.Date)
    {
        return 0;
    }
    int totalDays = (int)end.Date.Subtract(start.Date).TotalDays;
    DayOfWeek startDay = start.DayOfWeek;
    DayOfWeek endDay = end.DayOfWeek;
    ///look if endDay appears before or after the selectedDay when we start from startDay.
    int startToEnd = (int)endDay - (int)startDay;
    if (startToEnd < 0)
    {
        startToEnd += 7;
    }
    int startToSelected = (int)selectedDay - (int)startDay;
    if (startToSelected < 0)
    {
        startToSelected += 7;
    }
    bool isSelectedBetweenStartAndEnd = startToEnd >= startToSelected;
    if (isSelectedBetweenStartAndEnd)
    {
        return totalDays / 7 + 1;
    }
    else
    {
        return totalDays / 7;
    }
}

答案 9 :(得分:1)

如果您想在两个日期之间获得特定的工作日,您可以尝试这样做
public List<DateTime> GetSelectedDaysInPeriod(DateTime startDate, DateTime endDate, List<DayOfWeek> daysToCheck)
{
    var selectedDates = new List<DateTime>();

    if (startDate >= endDate)
        return selectedDates; //No days to return

    if (daysToCheck == null || daysToCheck.Count == 0)
        return selectedDates; //No days to select

    try
    {
        //Get the total number of days between the two dates
        var totalDays = (int)endDate.Subtract(startDate).TotalDays;

        //So.. we're creating a list of all dates between the two dates:
        var allDatesQry = from d in Enumerable.Range(1, totalDays)
                             select new DateTime(
                                                  startDate.AddDays(d).Year,
                                                  startDate.AddDays(d).Month,
                                                  startDate.AddDays(d).Day);

        //And extracting those weekdays we explicitly wanted to return
        var selectedDatesQry = from d in allDatesQry
                                  where daysToCheck.Contains(d.DayOfWeek)
                                  select d;

        //Copying the IEnumerable to a List
        selectedDates = selectedDatesQry.ToList();
    }
    catch (Exception ex)
    {
        //Log error
        //...

        //And re-throw
        throw;
    }
    return selectedDates;
}

答案 10 :(得分:1)

这将返回一个整数集合,显示在一个日期范围内每周发生的次数

    int[] CountDays(DateTime firstDate, DateTime lastDate)
    {
        var totalDays = lastDate.Date.Subtract(firstDate.Date).TotalDays + 1;
        var weeks = (int)Math.Floor(totalDays / 7);

        var result = Enumerable.Repeat<int>(weeks, 7).ToArray();
        if (totalDays % 7 != 0)
        {
            int firstDayOfWeek = (int)firstDate.DayOfWeek;
            int lastDayOfWeek = (int)lastDate.DayOfWeek;
            if (lastDayOfWeek < firstDayOfWeek)
                lastDayOfWeek += 7;
            for (int dayOfWeek = firstDayOfWeek; dayOfWeek <= lastDayOfWeek; dayOfWeek++)
                result[dayOfWeek % 7]++;
        }
        return result;
    }

或稍微变化,让你做FirstDate.TotalDaysOfWeeks(SecondDate)并返回一个字典

    public static Dictionary<DayOfWeek, int> TotalDaysOfWeeks(this DateTime firstDate, DateTime lastDate)
    {
        var totalDays = lastDate.Date.Subtract(firstDate.Date).TotalDays + 1;
        var weeks = (int)Math.Floor(totalDays / 7);

        var resultArray = Enumerable.Repeat<int>(weeks, 7).ToArray();
        if (totalDays % 7 != 0)
        {
            int firstDayOfWeek = (int)firstDate.DayOfWeek;
            int lastDayOfWeek = (int)lastDate.DayOfWeek;
            if (lastDayOfWeek < firstDayOfWeek)
                lastDayOfWeek += 7;
            for (int dayOfWeek = firstDayOfWeek; dayOfWeek <= lastDayOfWeek; dayOfWeek++)
                resultArray[dayOfWeek % 7]++;
        }
        var result = new Dictionary<DayOfWeek, int>();
        for (int dayOfWeek = 0; dayOfWeek < 7; dayOfWeek++)
            result[(DayOfWeek)dayOfWeek] = resultArray[dayOfWeek];
        return result;
    }

答案 11 :(得分:0)

我的报告也有类似的问题。我需要两个日期之间的工作日数。 我可以在日期中循环并计算,但我的离散数学训练不会让我。这是我在VBA中编写的函数,用于获取两个日期之间的工作日数。我确定.net有类似的WeekDay功能。

   1  
   2  ' WorkDays
   3  ' returns the number of working days between two dates
   4  Public Function WorkDays(ByVal dtBegin As Date, ByVal dtEnd As Date) As Long
   5  
   6     Dim dtFirstSunday As Date
   7     Dim dtLastSaturday As Date
   8     Dim lngWorkDays As Long
   9  
  10     ' get first sunday in range
  11     dtFirstSunday = dtBegin + ((8 - Weekday(dtBegin)) Mod 7)
  12  
  13     ' get last saturday in range
  14     dtLastSaturday = dtEnd - (Weekday(dtEnd) Mod 7)
  15  
  16     ' get work days between first sunday and last saturday
  17     lngWorkDays = (((dtLastSaturday - dtFirstSunday) + 1) / 7) * 5
  18  
  19     ' if first sunday is not begin date
  20     If dtFirstSunday <> dtBegin Then
  21  
  22        ' assume first sunday is after begin date
  23        ' add workdays from begin date to first sunday
  24        lngWorkDays = lngWorkDays + (7 - Weekday(dtBegin))
  25  
  26     End If
  27  
  28     ' if last saturday is not end date
  29     If dtLastSaturday <> dtEnd Then
  30  
  31        ' assume last saturday is before end date
  32        ' add workdays from last saturday to end date
  33        lngWorkDays = lngWorkDays + (Weekday(dtEnd) - 1)
  34  
  35     End If
  36  
  37     ' return working days
  38     WorkDays = lngWorkDays
  39  
  40  End Function

答案 12 :(得分:0)

private System.Int32 CountDaysOfWeek(System.DayOfWeek dayOfWeek, System.DateTime date1, System.DateTime date2)
{
  System.DateTime EndDate;
  System.DateTime StartDate;

  if (date1 > date2)
  {
    StartDate = date2;
    EndDate = date1;
  }
  else
  {
    StartDate = date1;
    EndDate = date2;
  }

  while (StartDate.DayOfWeek != dayOfWeek)
    StartDate = StartDate.AddDays(1);

  return EndDate.Subtract(StartDate).Days / 7 + 1;
}

答案 13 :(得分:0)

四年后,我以为我会参加考试:

[TestMethod]
public void ShouldFindFridaysInTimeSpan()
{
    //reference: http://stackoverflow.com/questions/248273/count-number-of-mondays-in-a-given-date-range

    var spanOfSixtyDays = new TimeSpan(60, 0, 0, 0);
    var setOfDates = new List<DateTime>(spanOfSixtyDays.Days);
    var now = DateTime.Now;

    for(int i = 0; i < spanOfSixtyDays.Days; i++)
    {
        setOfDates.Add(now.AddDays(i));
    }

    Assert.IsTrue(setOfDates.Count == 60,
        "The expected number of days is not here.");

    var fridays = setOfDates.Where(i => i.DayOfWeek == DayOfWeek.Friday);

    Assert.IsTrue(fridays.Count() > 0,
        "The expected Friday days are not here.");
    Assert.IsTrue(fridays.First() == setOfDates.First(i => i.DayOfWeek == DayOfWeek.Friday),
        "The expected first Friday day is not here.");
    Assert.IsTrue(fridays.Last() == setOfDates.Last(i => i.DayOfWeek == DayOfWeek.Friday),
        "The expected last Friday day is not here.");
}

我对TimeSpan的使用有点矫枉过正 - 实际上我想直接查询TimeSpan

答案 14 :(得分:0)

经过修改的代码在这里可以正常工作并由我测试

        private int CountDays(DayOfWeek day, DateTime startDate, DateTime endDate)
        {
            int dayCount = 0;

            for (DateTime dt = startDate; dt < endDate; dt = dt.AddDays(1.0))
            {
                if (dt.DayOfWeek == day)
                {
                    dayCount++;
                }
            }

            return dayCount;
        }

示例:

int Days = CountDays(DayOfWeek.Friday, Convert.ToDateTime("2019-07-04"), 
             Convert.ToDateTime("2019-07-27")).ToString();