Web服务不能正常工作?

时间:2014-07-24 12:55:16

标签: android eclipse web-services ksoap2

我有一个我在IIS中创建的网站和一个在VS.net中创建的Web服务...当我通过浏览器访问网站时,我可以访问该网站并使用所有WebMethods但是当我尝试通过我的Eclipse Android项目访问它,它刚刚赢得了连接...我已经跟随了多个教程并得到了相同的结果。有没有人知道为什么会发生这种情况?

EDIT1

我的response.Dump是这样的:

401 - Unauthorized: Access is denied due to invalid credentials

虽然捕获的例外是:

org.xmlpull.v1.XmlPullParserException: expected: START_TAG {http://schemas.xmlsoap.org/soap/envelope/}Envelope (position:START_TAG <html>@2:44 in java.io.InputStreamReader@21f07348)

以下是代码:

public void getMessage() {

    private final String NAMESPACE   =  "http://tempuri.org/";
    private final String URL         =  "http://foo/blah/Service1.asmx";
    private final String SOAP_ACTION =  "http://tempuri.org/HelloWorld";
    private final String METHOD_NAME =  "HelloWorld";
    private  String TAG              =  "SOAP";

private static String message;
        String dump;
        //Create request
        SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);

        //Create envelope
        SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
                SoapEnvelope.VER10);
        //envelope.encodingStyle = SoapSerializationEnvelope.ENC2001;
        envelope.dotNet = true;



        //Set output SOAP object
        envelope.setOutputSoapObject(request);
        //Create HTTP call object
        HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);

        try {

            androidHttpTransport.debug=true;
            androidHttpTransport.call(SOAP_ACTION, envelope );
            dump = androidHttpTransport.responseDump;
            //Get the response
            SoapObject response = (SoapObject) envelope.getResponse();
            String result = (response.getProperty(0).toString());
            //SoapPrimitive response = (SoapPrimitive) envelope.getResponse();
            //Assign it to fahren static variable

            message = result.toString();

    } catch (Exception e) {
        //tv.setText(e.getMessage());
        e.printStackTrace();
    }

}

0 个答案:

没有答案