Question

我目前有两个功能测试：

用户登录测试

$I = new FunctionalTester($scenario);
$I->am('wedding guest');
$I->wantTo('Sign in to the website and see the home page');
$I->logIn('user@mysite.nl', 'secret');

$I->seeCurrentUrlEquals('');

$I->see('user page string');

管理员登录测试

$I = new FunctionalTester($scenario);

$I->am('The website admin');

$I->wantTo('Sign in to the website and see the admin page');

$I->login('admin@mysite.nl', 'mypass');

$I->seeCurrentUrlEquals('/admin');

登录方法的代码如下：

public function login($email, $password){
    $I = $this->getModule('Laravel4');
    $I->amOnPage('login');
    $I->fillField("email", $email);
    $I->fillField("password",  $password);
    $I->click("Log in!");
}

当我单独运行每个测试时，它们会成功，但是当我运行整个功能套件时（只有这两个测试是套件的一部分），我收到以下错误：

vendor/bin/codecept run functional
...
Functional Tests (2) ------------------------------------------------------------------------------------------------------------
Trying to Sign in to the website and see the admin page (SignInWebsiteAdminCept)                                           Ok
...

1) Failed to sign in to the website and see the home page in 
SignInUserCept (/var/www/tests/functional/SignInUserCept.php)
Couldn't login "user@mysite.nl","secret":
Symfony\Component\HttpKernel\Exception\NotFoundHttpException:
...
#1  /var/www/vendor/laravel/framework/src/Illuminate/Routing/Router.php:1049
#2  /var/www/vendor/laravel/framework/src/Illuminate/Routing/Router.php:1017
#3  /var/www/vendor/laravel/framework/src/Illuminate/Routing/Router.php:996
#4  /var/www/vendor/laravel/framework/src/Illuminate/Foundation/Application.php:776
#5  /var/www/vendor/laravel/framework/src/Illuminate/Foundation/Application.php:746
#6  /var/www/vendor/symfony/http-kernel/Symfony/Component/HttpKernel/Client.php:81
#7  /var/www/vendor/symfony/browser-kit/Symfony/Component/BrowserKit/Client.php:332
#8  /var/www/tests/_support/FunctionalHelper.php:15
#9  /var/www/tests/functional/FunctionalTester.php:369
#10 /var/www/tests/functional/SignInWeddingGuestCept.php:7

它似乎无法找到路线，但它显然存在，因为我能够通过执行$ vendor/bin/codecept run functional SignInUserCept.php成功运行测试

这是我的错误还是代码中的错误？我试过启用过滤器，没有运气。我似乎也无法将环境设置为local而不是testing。

Answer 1

有同样的问题！终于想通了。它似乎是Codeception v2.0.3中的一个错误

在您的composer.json中，暂时将版本设置为2.0.2（直到在将来的版本中修复）

"codeception/codeception": "2.0.2"

然后运行composer update以反映更改：

php composer.phar update

所有测试现在应该在一起运行时起作用。希望它适合你！

一起运行时，代码功能测试失败，在Laravel中单独运行时成功

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