Question

我有一个难题。从概念上讲，我想我知道自己需要做什么。代码方面，我不太确定。

我想通过AVAIL_NURSE_W1[]数组（其中包含与Week_1中哪个护士相对应的数字），生成一个随机数来决定该数组中的一个插槽（如果该插槽保持为零）值，然后生成另一个随机数并再试一次），取这个数字（这是一名护士），并将其放入MONDAY[]数组。

相关代码：

int main() {

int randomNurse();
srand(time_t(NULL));

/*0 = Denise, 1 = Inja, 2 = Jane, 3 = Karen, 4 = Maggie, 5 = Margaret, 6 = MJ, 7 = Queen, 8 = Sherri*/


/*-----WEEKLY_ASSIGNMENT-----*/

int AVAIL_NURSE_W1[] = { 1, 2, 3, 4, 5, 6, 7, 8, 9 }; //holds the numerical values of the nurses that CAN work each week

/*scans in first week*/
for (int column = 0; column < 4; column++) {
    for (int num = 0; num < 9; num++) {
        if (AVAIL_NURSE_W1[num] == select[0][column])
            AVAIL_NURSE_W1[num] = 0;
    }
}


/*-----MONDAY-----*/
int MONDAY[5]; //days of the week, number of jobs on a given day
for (int e = 0; e < 5; e++) { //loop for positions on monday
    while (MONDAY[e] == 0) {
        int temp_assign = randomNurse();
        if (AVAIL_NURSE_W1[temp_assign] != 0) { //if the nurse IS available...
            MONDAY[e] = AVAIL_NURSE_W1[temp_assign];
            AVAIL_NURSE_W1[temp_assign] = 0; //we don't want to repeat nurses
        } else {
            continue;
        }
    }
} 

return 0;
}

/*function to generate random nurse*/
int randomNurse() {

return rand() % 9; //random number 0-8, to pick nurse
}

我的问题：
我如何处理从AVAIL_NURSE_W1[]数组中获取可用护士，生成一个随机数，该数字决定从哪个槽中获取值，获取该值，将其存储在新数组MONDAY[]中;如果AVAIL_NURSE_W1[]数组中的值为零，则重复上述过程，直到选择非零值为止;选择一个值后，我会将所选值更改为零，然后再次循环。

期望的结果
MONDAY[]数组应包含五个非零整数。没有重复。

到目前为止，while循环条件似乎永远不会改变。

如果还有其他需要说的话，请告诉我。我希望我已经提供了足够的信息。

Answer 1

你走了：

#include<stdio.h>
#include <stdlib.h>

const char names[9][10] = {"Denise", "Inja", "Jane", "Karen", "Maggie", "Margaret",       "MJ", "Queen", "Sherri"};
const char days[5][10] = {"Monday", "Tuesday", "Wednesday", "Thursday", "Friday"};
int randomNurse();

int main() {


srand(time(NULL));
int day, e, pos, candidate;
int i,j;

/*0 = Denise, 1 = Inja, 2 = Jane, 3 = Karen, 4 = Maggie, 5 = Margaret, 6 = MJ, 7 = Queen, 8 = Sherri*/


/*-----WEEKLY_ASSIGNMENT-----*/

int AVAIL_NURSE_W1[9] = {1, 1, 1, 1, 1, 1, 1, 1, 1}; //holds the status of each nurse, 1:available 0:unavailable

int pos_per_day[5] = {2, 5, 7, 4, 3}; // number of needed nurses per day, Monday:2 nurses, tuesday: 5 nurses ...

int select[5][9]; // the selected nurses per day 
for(i=0; i<5; i++)
for(j=0; j<9;j++) select[i][j] = -1; // initialize to -1 which means no nurse is selected


// fill all the days of week 

for (day = 0; day<5; day++)   // for every day
{
    for(pos = 0; pos<pos_per_day[day]; pos++ ) // for every position needed that day
    {
        do
        {
            candidate = randomNurse();
        }while(!AVAIL_NURSE_W1[candidate]); // look for available nurse

        AVAIL_NURSE_W1[candidate] = 0;  // change her status to not available
        select[day][pos] = candidate;   // fill the output array with appropriate nurse
    }
    for(i=0; i< 9; i++)
    {
        AVAIL_NURSE_W1[i] = 1; // initialize the nurses status for next day use
    }
}

for(i=0; i<5; i++) // display 
{
    printf("%-10s: ", days[i]);
    for(j=0; j<9;j++) 
    {
        if(select[i][j] != -1) printf("%-10s ", names[select[i][j]]);
    }
    printf("\n");
}


return 0;
}

/*function to generate random nurse*/
int randomNurse() {

return rand() % 9; //random number 0-8, to pick nurse
}

循环创建随机数，从现有数组中读取，然后创建新数组 - 陷入While-Loop

1 个答案: