我有两个查询，都提供inventory.id，inventory.title和订单所需的金额。
我想要的是将它们组合在一起，以便将amount_needed_for_orders列的结果汇总在一起。
以下是对正在发生的事情的快速总结。我正在研究面包店库存管理计划。面包师有库存，面团食谱和面团配方的部分产品。
这是复杂/拔毛开始的地方。
每个配方都有成分列表，产量很高。 ***有些食谱中含有另一种食谱作为配料。面团中的这种面团被称为优选，也被称为池。
一个查询提供任意订单所需的库存量，第二个查询提供当前库存水平以及订单所需的库存量（不包括任何优惠成分）。
由于它很复杂，我正在建造它。下一步是以某种方式组合这两个查询。
以下是所有订单所需的库存量（不包括优惠）：
SELECT SUM(dough_recipe_ingredient_pounds / dough_recipe_yield_pounds * weight *
quantity_to_be_baked) as amount_needed_for_orders,id,title,inventory_pounds
FROM (
SELECT
inventory.id,
inventory.title,
products.weight,
products.id AS product_id,
(orders_items.quantity - orders_items.quantity_baked) AS
quantity_to_be_baked,
CASE inventory.units
WHEN 'kilograms'
THEN 2.20462 * inventory.quantity
WHEN 'pounds'
THEN 1 * inventory.quantity
WHEN 'ounces'
THEN 0.0625 * inventory.quantity
WHEN 'grams'
THEN 0.00220462 * inventory.quantity
END as inventory_pounds,
CASE dough_recipes.units
WHEN 'kilograms'
THEN 2.20462 * dough_recipes.amount
WHEN 'pounds'
THEN 1 * dough_recipes.amount
WHEN 'ounces'
THEN 0.0625 * dough_recipes.amount
WHEN 'grams'
THEN 0.00220462 * dough_recipes.amount
END AS dough_recipe_ingredient_pounds,
(orders_items.quantity - orders_items.quantity_baked) AS num_loaves_needed,
CASE doughs.units
WHEN 'kilograms'
THEN 2.20462 * doughs.yield
WHEN 'pounds'
THEN 1 * doughs.yield
WHEN 'ounces'
THEN 0.0625 * doughs.yield
WHEN 'grams'
THEN 0.00220462 * doughs.yield
END AS dough_recipe_yield_pounds
FROM inventory
LEFT JOIN dough_recipes ON inventory.id = dough_recipes.inventory_id
LEFT JOIN products ON dough_recipes.dough_id = products.dough_id
LEFT JOIN orders_items ON products.id = orders_items.product_id AND
(orders_items.quantity - orders_items.quantity_baked) > 0
LEFT JOIN doughs ON doughs.id = products.dough_id
) sq
GROUP BY id
以下是所有订单所需的广告资源量。
SELECT id,title, SUM(pre_ferment_recipe_ingredient_pounds /
pre_ferment_recipe_yield_pounds * weight * quantity_to_be_prepared) as
amount_needed_for_orders
FROM (SELECT inventory.id,
inventory.title,
dough_pre_ferments.amount,
dough_pre_ferments.unit,
products.weight,
(order_preferments.quantity-order_preferments.quantity_prepared) as
quantity_to_be_prepared,
CASE pre_ferment_recipes.units
WHEN 'kilograms'
THEN 2.20462 * pre_ferment_recipes.amount
WHEN 'pounds'
THEN 1 * pre_ferment_recipes.amount
WHEN 'ounces'
THEN 0.0625 * pre_ferment_recipes.amount
WHEN 'grams'
THEN 0.00220462 * pre_ferment_recipes.amount
END AS pre_ferment_recipe_ingredient_pounds,
CASE pre_ferments.units
WHEN 'kilograms'
THEN 2.20462 * pre_ferments.yield
WHEN 'pounds'
THEN 1 * pre_ferments.yield
WHEN 'ounces'
THEN 0.0625 * pre_ferments.yield
WHEN 'grams'
THEN 0.00220462 * pre_ferments.yield
END AS pre_ferment_recipe_yield_pounds
FROM inventory
LEFT JOIN pre_ferment_recipes ON pre_ferment_recipes.inventory_id =
inventory.id
LEFT JOIN dough_pre_ferments ON dough_pre_ferments.pre_ferment_id =
pre_ferment_recipes.pre_ferment_id
LEFT JOIN products ON products.dough_id = dough_pre_ferments.dough_id
LEFT JOIN pre_ferments ON pre_ferments.id =
pre_ferment_recipes.pre_ferment_id
LEFT JOIN order_preferments ON order_preferments.preferment_id =
pre_ferment_recipes.pre_ferment_id
) sq
GROUP BY id
答案 0 :(得分：1)
这是您问题的有效解决方案。
SELECT id, title, SUM(amount_needed_for_orders)
FROM(
(SELECT id,title, SUM(dough_recipe_ingredient_pounds / dough_recipe_yield_pounds * weight *
quantity_to_be_baked) as amount_needed_for_orders
FROM (
SELECT
inventory.id,
inventory.title,
products.weight,
products.id AS product_id,
(orders_items.quantity - orders_items.quantity_baked) AS
quantity_to_be_baked,
CASE inventory.units
WHEN 'kilograms'
THEN 2.20462 * inventory.quantity
WHEN 'pounds'
THEN 1 * inventory.quantity
WHEN 'ounces'
THEN 0.0625 * inventory.quantity
WHEN 'grams'
THEN 0.00220462 * inventory.quantity
END as inventory_pounds,
CASE dough_recipes.units
WHEN 'kilograms'
THEN 2.20462 * dough_recipes.amount
WHEN 'pounds'
THEN 1 * dough_recipes.amount
WHEN 'ounces'
THEN 0.0625 * dough_recipes.amount
WHEN 'grams'
THEN 0.00220462 * dough_recipes.amount
END AS dough_recipe_ingredient_pounds,
(orders_items.quantity - orders_items.quantity_baked) AS num_loaves_needed,
CASE doughs.units
WHEN 'kilograms'
THEN 2.20462 * doughs.yield
WHEN 'pounds'
THEN 1 * doughs.yield
WHEN 'ounces'
THEN 0.0625 * doughs.yield
WHEN 'grams'
THEN 0.00220462 * doughs.yield
END AS dough_recipe_yield_pounds
FROM inventory
LEFT JOIN dough_recipes ON inventory.id = dough_recipes.inventory_id
LEFT JOIN products ON dough_recipes.dough_id = products.dough_id
LEFT JOIN orders_items ON products.id = orders_items.product_id AND
(orders_items.quantity - orders_items.quantity_baked) > 0
LEFT JOIN doughs ON doughs.id = products.dough_id
) sq
GROUP BY id
)
UNION ALL
(SELECT id,title, SUM(pre_ferment_recipe_ingredient_pounds /
pre_ferment_recipe_yield_pounds * weight * quantity_to_be_prepared) as
amount_needed_for_orders
FROM (SELECT inventory.id,
inventory.title,
dough_pre_ferments.amount,
dough_pre_ferments.unit,
products.weight,
(order_preferments.quantity-order_preferments.quantity_prepared) as
quantity_to_be_prepared,
CASE pre_ferment_recipes.units
WHEN 'kilograms'
THEN 2.20462 * pre_ferment_recipes.amount
WHEN 'pounds'
THEN 1 * pre_ferment_recipes.amount
WHEN 'ounces'
THEN 0.0625 * pre_ferment_recipes.amount
WHEN 'grams'
THEN 0.00220462 * pre_ferment_recipes.amount
END AS pre_ferment_recipe_ingredient_pounds,
CASE pre_ferments.units
WHEN 'kilograms'
THEN 2.20462 * pre_ferments.yield
WHEN 'pounds'
THEN 1 * pre_ferments.yield
WHEN 'ounces'
THEN 0.0625 * pre_ferments.yield
WHEN 'grams'
THEN 0.00220462 * pre_ferments.yield
END AS pre_ferment_recipe_yield_pounds
FROM inventory
LEFT JOIN pre_ferment_recipes ON pre_ferment_recipes.inventory_id =
inventory.id
LEFT JOIN dough_pre_ferments ON dough_pre_ferments.pre_ferment_id =
pre_ferment_recipes.pre_ferment_id
LEFT JOIN products ON products.dough_id = dough_pre_ferments.dough_id
LEFT JOIN pre_ferments ON pre_ferments.id =
pre_ferment_recipes.pre_ferment_id
LEFT JOIN order_preferments ON order_preferments.preferment_id =
pre_ferment_recipes.pre_ferment_id
) sq
GROUP BY id
)
) as t
GROUP BY id
修改
这是一个带连接的工作解决方案。
SELECT
t.id, t.title, t.inventory_pounds,
t.amount_needed_for_orders + t1.amount_needed_for_orders
FROM(
SELECT
id,title, inventory_pounds,
SUM(dough_recipe_ingredient_pounds / dough_recipe_yield_pounds * weight * quantity_to_be_baked) AS amount_needed_for_orders
FROM (
SELECT
inventory.id,
inventory.title,
products.weight,
products.id AS product_id,
(orders_items.quantity - orders_items.quantity_baked) AS quantity_to_be_baked,
CASE inventory.units
WHEN 'kilograms'
THEN 2.20462 * inventory.quantity
WHEN 'pounds'
THEN 1 * inventory.quantity
WHEN 'ounces'
THEN 0.0625 * inventory.quantity
WHEN 'grams'
THEN 0.00220462 * inventory.quantity
END AS inventory_pounds,
CASE dough_recipes.units
WHEN 'kilograms'
THEN 2.20462 * dough_recipes.amount
WHEN 'pounds'
THEN 1 * dough_recipes.amount
WHEN 'ounces'
THEN 0.0625 * dough_recipes.amount
WHEN 'grams'
THEN 0.00220462 * dough_recipes.amount
END AS dough_recipe_ingredient_pounds,
(orders_items.quantity - orders_items.quantity_baked) AS num_loaves_needed,
CASE doughs.units
WHEN 'kilograms'
THEN 2.20462 * doughs.yield
WHEN 'pounds'
THEN 1 * doughs.yield
WHEN 'ounces'
THEN 0.0625 * doughs.yield
WHEN 'grams'
THEN 0.00220462 * doughs.yield
END AS dough_recipe_yield_pounds
FROM inventory
LEFT JOIN dough_recipes ON inventory.id = dough_recipes.inventory_id
LEFT JOIN products ON dough_recipes.dough_id = products.dough_id
LEFT JOIN orders_items ON products.id = orders_items.product_id AND
(orders_items.quantity - orders_items.quantity_baked) > 0
LEFT JOIN doughs ON doughs.id = products.dough_id
) sq
GROUP BY id
) AS t
JOIN
( SELECT
id,title,
SUM(pre_ferment_recipe_ingredient_pounds / pre_ferment_recipe_yield_pounds * weight * quantity_to_be_prepared) AS amount_needed_for_orders
FROM (SELECT inventory.id,
inventory.title,
dough_pre_ferments.amount,
dough_pre_ferments.unit,
products.weight,
(order_preferments.quantity-order_preferments.quantity_prepared) AS
quantity_to_be_prepared,
CASE pre_ferment_recipes.units
WHEN 'kilograms'
THEN 2.20462 * pre_ferment_recipes.amount
WHEN 'pounds'
THEN 1 * pre_ferment_recipes.amount
WHEN 'ounces'
THEN 0.0625 * pre_ferment_recipes.amount
WHEN 'grams'
THEN 0.00220462 * pre_ferment_recipes.amount
END AS pre_ferment_recipe_ingredient_pounds,
CASE pre_ferments.units
WHEN 'kilograms'
THEN 2.20462 * pre_ferments.yield
WHEN 'pounds'
THEN 1 * pre_ferments.yield
WHEN 'ounces'
THEN 0.0625 * pre_ferments.yield
WHEN 'grams'
THEN 0.00220462 * pre_ferments.yield
END AS pre_ferment_recipe_yield_pounds
FROM inventory
LEFT JOIN pre_ferment_recipes ON pre_ferment_recipes.inventory_id = inventory.id
LEFT JOIN dough_pre_ferments ON dough_pre_ferments.pre_ferment_id = pre_ferment_recipes.pre_ferment_id
LEFT JOIN products ON products.dough_id = dough_pre_ferments.dough_id
LEFT JOIN pre_ferments ON pre_ferments.id = pre_ferment_recipes.pre_ferment_id
LEFT JOIN order_preferments ON order_preferments.preferment_id = pre_ferment_recipes.pre_ferment_id
) sq
GROUP BY id
) AS t1 ON t.id = t1.id
GROUP BY id
答案 1 :(得分：0)
由于您说性能不是问题，您可以使用UNION和聚合函数来获取总和。
首先，您必须重新排列查询列才能执行联合。您需要以相同的顺序使用相同的列。所以我将inventory_pounds作为0添加到第二个查询中，您可以编写适当的SQL来正确获取它。 （或者如果可能的话，你可以从第一个查询中遗漏inventory_pounds。
SELECT id, title, inventory_pounds, SUM(dough_recipe_ingredient_pounds / dough_recipe_yield_pounds * weight *
quantity_to_be_baked) as amount_needed_for_orders,
FROM (...)
GROUP BY id
SELECT id, title, 0 as inventory_pounds, SUM(pre_ferment_recipe_ingredient_pounds /
pre_ferment_recipe_yield_pounds * weight * quantity_to_be_prepared) as
amount_needed_for_orders
FROM (...)
GROUP BY id
然后，您可以对两个查询执行UNION：
(SELECT id, title, inventory_pounds, SUM(dough_recipe_ingredient_pounds ...)
UNION
(SELECT id, title, 0 as inventory_pounds, SUM(pre_ferment_recipe_ingredient_pounds ...)
现在这可能包含重复的id个。所以使用GROUP BY进行SUM。
SELECT id, title,
SUM(inventory_punds) as sum_pounds,
SUM(amount_needed_for_orders) sum_amount_needed_for_orders
FROM
(SELECT id, title, inventory_pounds, SUM(dough_recipe_ingredient_pounds ...)
UNION
(SELECT id, title, 0 as inventory_pounds, SUM(pre_ferment_recipe_ingredient_pounds ...)
GROUP BY id, title;