仅查找连接条件匹配的父项

Question

我有两个相关的模型。现在我需要从Field-Model中检索UserField上的连接条件匹配的数据：

我有UserField的ID并希望得到它的相关字段（-data）： 相应的sql看起来像这样：

SELECT Field.* 
FROM fields AS Field 
  JOIN user_fields AS UserField 
    ON UserField.field_id = Field.id 
WHERE UserField.id = 3;

我想用蛋糕模型逻辑来写这个。

模型：

class Field extends AppModel {
     public $hasMany = array(
          'UserField' => array(
               'className' => 'UserField',
               'foreignKey' => 'field_id'
          )
     );
}

class UserField extends AppModel {
     public $belongsTo = array(
          'Field' => array(
               'className' => 'Field'
          )
     );
}

查找

$this->Field->hasMany['UserField']['conditions'] = array('UserField.id' => 3);
$this->Field->find('all');

查询的结果都是字段，而UserField仅在条件匹配时设置。我需要将结果限制为仅匹配的情况：

array(
    (int) 0 => array(
        'Field' => array(
            'id' => (int) 1
        ),
        'UserField' => array()
    ),
    (int) 1 => array(
        'Field' => array(
            'id' => (int) 2
        ),
        'UserField' => array()
    ),
    (int) 2 => array(
        'Field' => array(
            'id' => (int) 3
        ),
        'UserField' => array(
            'id' => (int) 3
        )
    )
)

我的期望

array(
    (int) 2 => array(
        'Field' => array(
            'id' => (int) 3
        ),
        'UserField' => array(
            'id' => (int) 3
        )
    )
)

UserField是可选的，我只想检索Field数据。

Answer 1

你想做这样的事我相信：

$rows = $this->Field->find('all', array(
    'conditions' => array(
        'UserField.id' => 3
    )
);